1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marina CMI [18]
3 years ago
6

If a ball is thrown straight up into the air with an initial velocity of 40 ft/s, it height in feet after t second is given by y

=40t−16t2. Find the average velocity for the time period begining when t=2 and lasting
(i) 0.5 seconds

(ii) 0.1 seconds

(iii) 0.01 seconds

Finally based on the above results, guess what the instantaneous velocity of the ball is when t=2.
Physics
1 answer:
Tasya [4]3 years ago
5 0
We should first calculate the highest point that ball reaches. 
y' = 40 - 32t = 0
t = 40/32 = 1,25s
y = 25 feet.

To calculate average velocity we use simple formula:
Vav=s/t   where s is traveled distance by the time t.



for t=2  we calculate y
y = 16
(i)  for t = 2,5     y = 0
Vav = 16/0.5 = 32 feet/s
(ii) for t = 2.1     y = 13.44
Vav = 2.56/0.1 = 25.6 feet/s
(iii) for t = 2.01  y = 15.7584
Vav = 0.2416/0.01= 24.16 feet/s

it seems like the answer would be 24 feet/s. There is a way to calculate that.
You might be interested in
Bill is farsighted and has a near point located 121 cm from his eyes. Anne is also farsighted, but her near point is 74.0 cm fro
Arada [10]

Answer:

Explanation:

The lens equation is

1 / f = 1 / di + 1 / do

Where

f is focal length

di is the image distance

do is the object distance

Both Annie and Billy use a glass whose near point is 25cm

Then, the object distance is

do = 25 - 2 = 23cm

The have the same object distance.

Let find the vocal length of bills eye

Given that,

Bill near point is 121cm and distance of the glass from the eye is 2cm

Then,

Image distance of bill is

di_B = -(121-2) = -119cm

object distance do = 23cm

Then,

1 / f_B = 1 / di_B + 1 / do

1 / f_B = -1 / 119 + 1 / 23

1 / f_B = -119^-1 + 23^-1

1 / f_B = 0.0351

Then, f_B = 28.51 cm

Also, let find Annie focal length

Given that,

Annie near point is 74 cm and distance of the glass from the eye is 2cm

Then,

Image distance of Annie is

di_A = -(74-2) = -72cm

object distance do = 23cm

Then,

1 / f_A = 1 / di_A + 1 / do

1 / f_A = -1 / 72 + 1 / 23

1 / f_A = -72^-1 + 23^-1

1 / f_A = 0.02959

Then, f_A = 33.8 cm

Distance of object from the lens when Annie uses Billy glass

Then,

1 / f_B = 1 / di_A + 1 / do

1 / 28.51 = -1 / 72 + 1 / do

28.51^-1 = -72^-1 + do^-1

do^-1 = 28.51^-1 + 72^-1

do^-1 = 0.048964

do = 20.42 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_A = 20.42 + 2 = 22.42cm

do_A = 22.42 cm

Distance of object from the lens when Billy uses Annie glass

Then,

1 / f_A = 1 / di_B + 1 / do

1 / 33.8 = -1 / 119 + 1 / do

33.8^-1 = -119^-1 + do^-1

do^-1 = 33.8^-1 + 119^-1

do^-1 = 0.03799

do = 26.32 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_B = 26.32 + 2 = 28.32 cm

do_B = 28.32 cm

7 0
3 years ago
What are the different ways that the simulation shows you that the equation is balanced, visually? For each balanced reaction, i
Nastasia [14]

Answer:

e

Explanation:

e

3 0
3 years ago
Two magnetic poles that repel one another are held three inches apart. What happens when the poles are moved closer together, to
dedylja [7]
Because of the magnets are actually electromagnetics aka what causes them to repel each other the atoms and the electrons will make a force of them pushing away from each other because the two magnetic poles are not north and south
3 0
3 years ago
Read 2 more answers
Help it’s actually physical science but plz help
Butoxors [25]
The correct answer is B
3 0
3 years ago
The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume tha
belka [17]

Given that,

Energy H=2.7\times10^{31}\ W

Surface temperature = 11000 K

Emissivity e =1

(a). We need to calculate the radius of the star

Using formula of energy

H=Ae\sigma T^4

A=\dfrac{H}{e\sigma T^4}

4\pi R^2=\dfrac{H}{e\sigma T^4}

R^2=\dfrac{H}{e\sigma T^4\times4\pi}

Put the value into the formula

R=\sqrt{\dfrac{2.7\times10^{31}}{1\times5.67\times10^{-8}\times(11000)^4\times 4\pi}}

R=5.0\times10^{10}\ m

(b). Given that,

Radiates energy H=2.1\times10^{23}\ W

Temperature T = 10000 K

We need to calculate the radius of the star

Using formula of radius

R^2=\dfrac{H}{e\sigma T^4\times4\pi}

Put the value into the formula

R=\sqrt{\dfrac{2.1\times10^{23}}{1\times5.67\times10^{-8}\times(10000)^4\times4\pi}}

R=5.42\times10^{6}\ m

Hence, (a). The radius of the star is 5.0\times10^{10}\ m

(b). The radius of the star is 5.42\times10^{6}\ m

8 0
3 years ago
Other questions:
  • Which equation would you use to solve the following problem? An object is moved 29 m with a force of 289 N. What is the work don
    8·1 answer
  • A toy car is moving across a table with a velocity of 7.0 m/s and drives off the end. The table is 1.8 m tall. How long will the
    7·1 answer
  • Q1 is located at the origin, Q2 is located at x = 2.50 cm and Q3 is located at x = 3.50 cm. Q1 has a charge of +4.92μC and Q3 ha
    6·1 answer
  • A little help please?
    12·1 answer
  • The student quickly discovers that placing the marshmallow over the flame is more effective than heating the marshmallow on the
    6·1 answer
  • A spherical shell of mass M and radius R is completely filled with a frictionless fluid, also of mass M. It is released from res
    8·1 answer
  • what happens to a circuits resistance, voltage, and current when you increase the diameter of the wire in the circuit?
    15·1 answer
  • A steel ball of mass 0.500 kg is fastened to a cord that is 70.0 cm long and fixed at the far end. The ball is then released whe
    15·1 answer
  • Kuhygtfchvgbjkniljuhygutyfvghbjkljhbvghuijohbiuljkhbjiuoljkhftgyjhvgjk
    13·1 answer
  • Q C During a solar eclipse, the Moon, the Earth, and the Sun all lie on the same line, with the Moon between the Earth and the S
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!