A 15-N force to the left and a 45-N force to the right act on a 10 kg object in opposite directions.

Physics

1 answer:

aleksley [76]3 years ago

6 0

Answer:

daddy

Explanation:

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A body moving in the positive x direction passes the origin at time t = 0. Between t=0 and t=1 second, the body has a constant s

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The important thing in this type of questions is to keep track of what you are doing at every point.

From t=0 to t=1s, there is uniform motion at v=24 m/s.

Therefore, it will move 24m in that second of time.

Afterwards, an acceleration comes in, so from t=1s to 11s there will be uniformly accelerated motion with acceleration -6m/s^2.

To account for this, you need to use Suvat's equation:

x(t)=x0+v0*t+1/2*a*t^2.

You should know what to plug in for each of the symbols in this equation:

x0 [initial position at t=1s] = 24m

v0 [initial velocity at t=1s] = 24 m/s

a [acceleration, switched on at t=1s] = -6 m/s^2

t [time from the start of the acceleration until the end, i.e. from t=1s to t=11s] = 10s

Plugging in those numbers in the equation will give you the position at t=11s.

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A 0.413 kg block requires 1.09 N

Virty [35]

Answer:

Explanation:

The equation for this is

f = μ $F_n$ where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and $F_n = w=mg$ (that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in: