The question that cannot be answered based on the information in the delivery truck data base is 2) What is the average number of customer deliveries made by each truck on a particular day?
<h3>Why can this question not be answered?</h3>
In order to answer this question, the number of customers that each truck delivered to during the day needs to be recorded.
The total number of deliveries will then be added up and divided by the number of trucks making deliveries.
The information on the number of deliveries made is not in the database so this question cannot be answered.
In conclusion, option 2 is correct.
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Answer and Explanation:
Q2) Calculate the amount that should be reported as net cash flow from operating activities:
Account Receivables = $40
Depreciation = $ 60
Since there is an in Account Receivables therefore it will be negative
Since depreciation is a non cash expense, therefore, it will be added
$60 - $40 = $20 (Net Cash flow from operating activities)
Q3) Amount as net income:
Revenue = $170
Depreciation ($60)
Net Income = $110
Q4)
Net inome = $170
Depreciation = $60
Increase in Accounts Receivables = ($40)
Net Cash flow from operating activities = $190
For every jar Neha buys, she spends $0.95, and buying 9 jars in total, she pays $8.55 in total.
$0.95 x 9 jars = $8.55
For every jar Neha buys, she spends $0.95, and buying 9 jars in total, she pays $8.55 in total.
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Answer:
Option (d) , Bank 4 offers the highest amount after a year
Explanation:
The total amount from each of the interest rates can be expressed as;
A=P(1+r/n)^nt
where;
A=Future value of investment
P=Initial value of investment
r=Annual interest rate
n=Number of times the interest is compounded annually
t=number of years of the investment
a). Bank 1
P=x
r=6.1%=6.1/100=0.061
n=1
t=assume number of years=1
replacing;
A=x(1+0.061/1)^(1×1)
A=x(1.061)
A=1.061 x
b). Bank 2
P=x
r=6%=6/100=0.06
n=12
t=1
Replacing;
A=x(1+0.06/12)^(12×1)
A=x(1.005)^12
A=1.0617 x
c). Bank 3
P=x
r=6%=6/100=0.06
n=1
t=1
Replacing;
A=x(1+0.06/1)^(1)
A=1.0600 x
d). Bank 4
P=x
r=6%=6/100=0.06
n=4
t=1
A=x(1+0.06/4)^(4×1)
A=x(1+0.015)^4
A=x(1.061)
A=1.0614 x
e). Bank 5
P=x
r=6%=6/100=0.06
n=365
t=1
A=x(1+0.06/365)^(365×1)
A=1.0618
Option (d) , Bank 4 offers the highest amount after a year
Answer:
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