Answer:
c=
−4
3
s−t+
−4
3
Step-by-step explanation:
Let's solve for c.
3s+2t−3c−7s−5t=4
Step 1: Add 4s to both sides.
−3c−4s−3t+4s=4+4s
−3c−3t=4s+4
Step 2: Add 3t to both sides.
−3c−3t+3t=4s+4+3t
−3c=4s+3t+4
Step 3: Divide both sides by -3.
−3c
−3
=
4s+3t+4
−3
c=
−4
3
s−t+
−4
3
Average speed is the distance traveled by an object in total and divided by the amount of time an object covers the distance. The formula is -
Average speed = total distance traveled / total time taken
= 68km+64km / 2 hrs.+3hrs.
= 132km / 5hrs.
= 26.4km/hr.
Therefore, the train's average speed is 26.4km/hr.
Add 2.2 to each side so 0.3z = 5.2 - 0.5z -0.8z
add 0.5z to each side so 0.8z = 5.2 - 0.8z
add 0.8z to each side so 1.4z = 5.2
divide each side by 1.4 so z = 3.71428571
Answer:
A. 11
Step-by-step explanation:
11-3=9
The set does not include 9 because the sign is not underlined so 11 is not a solution.
Answer:
yes it is not b/c
Step-by-step explanation:
if n is >5 ,5 is < n
