Question

NEED ANSWERS NOW!! (Reward) brainlest and pointsss

Answer 1

Answer:

B

Step-by-step explanation

f(x)=x2-4x-5

Becomes

f(x)=x2-5x+x-5

Take out the common factor

f(x)=(x-5)(x+1)

Equate the given function equal to 0

0=(x-5)(x+1)

And then

x-5=0 -- x=5

x+1 = 0 == x=-1

Answer 2

Answer:

B

Step-by-step explanation:

we are given a quadratic function

we want to figure out the form which we don't need change

so according to the question

$\displaystyle{x}^{2} - 4x - 5 = 0$

rewrite -4x as x-5x:

$\displaystyle{x}^{2} + x - 5x- 5 = 0$

factor out x:

$\displaystyle \: x({x}^{} + 1)- 5x- 5 = 0$

factor out -5:

$\displaystyle \: x({x}^{} + 1)- 5(x + 1 )= 0$

group:

$\displaystyle \: (x + 1 )(x - 5)= 0$

hence our answer is B