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Elanso [62]
4 years ago
12

A student measures a pressure increase of 0.25 atm while collecting the H2 gas products from the reaction of Mg with HCl. The th

eoretical pressure change is 0.29 atm. What is the % yield
Chemistry
1 answer:
natulia [17]4 years ago
7 0

Answer: Thus the % yield is 86.2%

Explanation:

Percentage yield is the ratio of actual change to the theoretical change in terms of percentage.

The given reaction is :

Mg+2HCl\rightarrow MgCl_2+H_2

To calculate the percent yield :

\%\text{ yield of reaction}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Given : Actual pressure increase = 0.25 atm

Theoretical pressure change = 0.29 atm.

\%\text{ yield of reaction}=\frac{0.25}{0.29}\times 100=86.2\%

Thus the % yield is 86.2%

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(a) Calculate the wavelength of light in vacuum that has a frequency of 5.49 ✕ 1018 Hz. 0.0546 Correct: Your answer is correct.
vfiekz [6]

Answer:

a) Wavelength of the light in vacuum = (5.46 × 10⁻¹¹) m = 0.0546 nm

b) Wavelength of the light in diamond = (2.26 × 10⁻¹¹) m = 0.0226 nm

c) Energy of one photon in vacuum = (3.638 × 10⁻¹⁵) J = (2.271 × 10⁴) eV

d) No, the energy of the photon doesn't change when it is travelling inside diamond.

Explanation:

Wavelength (λ), frequency (f) and velocity of light (v) are related as thus

v = fλ

a) v = fλ

v = velocity of light in vacuum = (3.0 × 10⁸) m/s

f = frequency of the light = (5.49 × 10¹⁸) Hz

λ = wavelength of the light = ?

λ = (v/f) = (3.0 × 10⁸) ÷ (5.49 × 10¹⁸)

= (5.46 × 10⁻¹¹) m = 0.0546 nm

b) To find the wavelength of the light in diamond, we need the refractive index of diamond. This is because light, just like all other waves, change their velocities and subsequently their wavelengths in different materials according to the refractive index of the materials.

Refractive index of diamond = 2.42 (from literature)

2.42 = (wavelength of light in vacuum) ÷ (wavelength of light in diamond)

2.42 = 0.0546 ÷ λ

λ = 0.0546 ÷ 2.42 = 0.0226 nm

c) Energy of a photon in vacuum is given as

E = hf

where E = energy in Joules = ?

h = Planck's constant = (6.626 × 10⁻³⁴) J.s

f = frequency of the light in vacuum = (5.49 × 10¹⁸) Hz

E = (6.626 × 10⁻³⁴) × (5.49 × 10¹⁸) = (3.638 × 10⁻¹⁵) J

1 eV = (1.602 × 10⁻¹⁹) J

The amount of the calculated energy in eV

= (3.638 × 10⁻¹⁵) ÷ (1.602 × 10⁻¹⁹) = (2.271 × 10⁴) eV

d) As light travels from material to material, it's velocity and wavelength changes from material to material, but the frequency of the light waves stay the same. Since the energy of the photon depends solely on this frequency, it shows that the energy of the photon stays consistent in whichever material.

Hope this Helps!!!

3 0
3 years ago
What are the concentrations of hydronium and hydroxide ions in a solution with pH 2.6?
Deffense [45]

Answer:

The concentrations of hydronium and hydroxide ions in a solution with pH 2.6 are 2.51*10⁻³ and 3.98*10⁻¹² respectively.

Explanation:

pH is a measure of the acidity or alkalinity of an aqueous solution. The pH indicates the concentration of hydrogen ions present in certain solutions. Mathematically it is defined as the opposite of the base 10 logarithm or the negative logarithm of the activity of hydrogen ions, whose equation is

pH= -log [H⁺]

So, being pH= 2.6 and replacing in the definition of pH:

2.6= -log [H⁺]

[H^{+} ]=10^{-2.6}

[H⁺]=2.51*10⁻³

pOH is a measure of the concentration of hydroxide ions (OH⁻). The sum between the pOH and the pH results in 14:

pOH + pH= 14

So, being pH= 2.6:

pOH + 2.6= 14

pOH= 14 - 2.6

pOH= 11.4

The pOH is defined as the negative logarithm of the activity of the hydroxide ions. That is, the concentration of OH⁻ ions:

pOH= - log [OH⁻]

Being pOH= 11.4 and replacing

11.4= -log [OH⁻]

[OH^{-} ]=10^{-11.4}

[OH⁻]= 3.98*10⁻¹²

<u><em>The concentrations of hydronium and hydroxide ions in a solution with pH 2.6 are 2.51*10⁻³ and 3.98*10⁻¹² respectively.</em></u>

6 0
3 years ago
How do I find the volume of a gas at stp if it’s volume is 80.0mL at 109kPa and -12.5 degrees Celsius
Hatshy [7]

all i really know is that STP (standard temperature and pressure) represents conventional conditions established by IUPAC with T = 273.15 K, P = 1 atm . Now putting these values of temperature and pressure at STP, we can calculate easily volume occupied by 1 mol of gas and which comes out to be 22.4 L. hope this helps

4 0
3 years ago
Read 2 more answers
Calculate the standard free-energy change for the following reaction at 25 °C. Standard reduction potentials can be found here.
Gelneren [198K]

Since there are no given data for us to solve this problem, I will explain what a Standard Reduction Potential is. For example, if a student had an experiment and he wanted to know what is the most efficient and powerful redox reaction involving an uncommon combination of chemicals. The student would most likely record information in the Standard Reduction Potential that showed the voltage generated by the reaction in Aqueous Solution at 25 degrees Celsius and 1 atmosphere. This is a list of half reaction of ions in the solution at standard temperature and pressure.

3 0
3 years ago
do you agree or disagree with the following statement: laws are more important than theories because were never really sure is t
Vladimir [108]

Answer:

I agree with laws.

Explanation:

because laws are always correct.

6 0
3 years ago
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