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DIA [1.3K]
3 years ago
11

Please help me with this homework

Chemistry
1 answer:
KengaRu [80]3 years ago
8 0

Answer:

The answer is C density.

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What do these two changes have in common?
Arada [10]

Answer: Both are only physical changes. •

Explanation:

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2 years ago
Ask Your Teacher You are given two clear, colorless aqueous solutions. You are told that one solution contains an ionic compound
Slav-nsk [51]

Answer:

Explanation:

Ionic compound are compounds formed by one atom losing an electron while the other gains electron as such the solution always contain charge ions compared to covalent solution which is predominantly formed by two atoms sharing electron. The two solution should be connected to a circuit with a bulb in turns with the same circuit, the solution that turns the  bulb on is the ionic solution. This is because their charged ions conducts electricity when voltage is passed through it while the covalent solution does not conduct electricity.

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3 years ago
What is the formula for finding the density of<br> an object?
TEA [102]
The answer would be:
D = M/V

D=Density
M= mass
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3 0
3 years ago
Read 2 more answers
PLEASE HELP 25 POINTS!!!!
Mariulka [41]

Answer:

1 is c 2 is b

Explanation:

because atomic number is the number of protons in a nucleus

2..because the number of protons plus number of neutrons is equal to mass number.

7 0
3 years ago
Question 4 (1 point)<br> If you have exactly one million atoms how many moles do you have?
rjkz [21]

Answer:

                       1.66 × 10⁻¹⁸  Moles

Explanation:

                     As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Atoms and Avogadro's Number is given as,

             Number of Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms/mol

Putting values,

              Number of Moles  =  1.0 × 10⁶ Atoms ÷ 6.022 × 10²³ Atoms/mol

              Number of Moles  =  1.66 × 10⁻¹⁸  Moles

7 0
4 years ago
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