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olya-2409 [2.1K]
3 years ago
10

1- N 2- Ne 3- Ar 4- P

Chemistry
1 answer:
dalvyx [7]3 years ago
3 0
The answer to this problem is

P - phosphorus
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Describe relationship between frequency, wavelength, and energy as you move up and down the spectrum.
nadya68 [22]
When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true.... as frequency decreases, wavelength increases.
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Describe how you could show that a compound is an acid
Charra [1.4K]
An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted. Now there are more hydrogen ions than hydroxide ions in the solution. This kind of solution is acidic.
5 0
3 years ago
A gas has a volume of 10.0 liters at 373K and a pressure of 5.0atm, what volume will the gas occupy at STP?
zhannawk [14.2K]
Use ideal gas law PV=nRT
Convert 5.00 atm to kPa since units must be relative to gas constant (r).
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Now plug in (506.5kPa)(10.0L)=n(8.31 L•atm/mol•K)(373K)
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4 0
4 years ago
What is the mass, in grams, of a sample of 7.83 × 1024 atoms of helium (He)? Show your work or explain the steps that you used t
timurjin [86]
First, we will get the number of moles:
one mole contains Avogadro's number of atoms. Therefore, to know the number of moles in <span>7.83 × 10^24 atoms, we will simply do cross multiplication as follows:
number of moles = (</span><span>7.83 × 10^24*1) / (6.022 * 10^23) = 13 moles

From the periodic table:
mass of one mole of helium = 4 grams
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7 0
4 years ago
Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer t
nekit [7.7K]

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

n = \frac{m}{M}

<u>Where:</u>

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

n = \frac{m}{M} = \frac{14 g}{56.1056 g/mol} = 0.249 mol

The enthalpy change is:

\Delta H = -43 \frac{kJ}{mol}*0.249 mol = -10.71 kJ

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

5 0
3 years ago
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