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Travka [436]
4 years ago
5

Page 705 #12/#13: Use the changes in oxidation numbers to identify which atom is oxidized, reduced, the oxidizing agent, and the

reducing agent. 5
A.
2H2(g) + O2(g) → 2H2O(l)

B.
2KNO3(s) → 2KNO2(s) + O2(g)

Chemistry
1 answer:
guapka [62]4 years ago
7 0

Concepts to understand before solving:

-Oxygen is ALWAYS reduced

-OIL- Oxidation Is Loss of electrons

-RIG- Reduction Is Gain of electrons

-the element that is oxidized is the reducing agent

-the element that is reduced is the oxidizing agent

A. 2H2 + O2 —> 2H2O

O is reduced, making it the oxidizing agent

H is oxidized, making it the reducing agent

B. 2KNO3 —> 2KNO2 + O2

O is reduced, making it the oxidizing agent

KNO is oxidized, making it the reducing agent

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How are different elements distinguishable from one another? (Check all that apply.)
Kazeer [188]
The correct answer to this question is the unique atomic number which would be B
7 0
3 years ago
0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction
algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce \frac{2}{1} = \frac{x}{0.50}

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

\frac{2}{2} = \frac{x}{0.6}

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

\frac{2}{3} = \frac{x}{0.9}

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0
3 years ago
A client with a long history of cigarette smoking and poorly controlled hypertension is
MaRussiya [10]

Answer:

It may be a hemorrhagic stroke because of the patient's history.

Explanation:

Uncontrolled hypertension could generate a hemorrhagic stroke within the brain generating the sign of progressive dementia, this is due to the vessel breaking due to the excess pressure of the internal light, it breaks and releases or extravases all the bloody contents to the brain

The difficulty of this is that the brain is the one that yields to a force in relation to the skull, that is why it is compressible against hemorrhage generating these signs as progressive dementia and could even be death or vegetative state

3 0
4 years ago
For the titration of 50. mL of 0.10 M ammonia with 0.10 M HCl, calculate the pH. For ammonia, NH3, Kb
Korolek [52]

Answer:

11.12 → pH

Explanation:

This is a titration of a weak base and a strong acid.

In the first step we did not add any acid, so our solution is totally ammonia.

Equation of neutralization is:

NH₃ + HCl → NH₄Cl

Equilibrium for ammonia is:

NH₃ + H₂O ⇄  NH₄⁺  +  OH⁻      Kb = 1.8×10⁻⁵

Initially we have 50 mL . 0.10M = 5 mmoles of ammonia

Our molar concentration is 0.1 M

X amount has reacted.

In the equilibrium we have (0.1 - x) moles of ammonia and we produced x amount of ammonium and hydroxides.

Expression for Kb is : x² / (0.1 - x)  = 1.8×10⁻⁵

As Kb is so small, we can avoid the x to solve a quadratic equation.

1.8×10⁻⁵ = x² / 0.1

1.8×10⁻⁵  .  0.1 = x²

1.8×10⁻⁶ = x²

√1.8×10⁻⁶ = x → 1.34×10⁻³

That's the value for [OH⁻] so:

1×10⁻¹⁴ = [OH⁻] . [H⁺]

1×10⁻¹⁴ / 1.34×10⁻³ = [H⁺] → 7.45×10⁻¹²

- log [H⁺] = pH

- log 7.45×10⁻¹² = 11.12 → pH

4 0
3 years ago
A car traveling in a northeasterly direction at a rate of 50 km/h represents which of the following?
EleoNora [17]

Answer:

B. velocity

Explanation:

Velocity is defined as speed in a given direction.

6 0
3 years ago
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