Answer:
The probability that the customer is charged incorrectly on at most 2 items is 3.979 × 10⁻².
Step-by-step explanation:
To solve the question, we note that we proceed with the binomial distribution formula as follows
Number of times the customer is incorrectly charged out of ever 10 items = 4
Therefore, the probability that the customer is incorrectly charged is 4/10 = 0.4
That is p(incorrect) = 0.4
Then the probability that the customer is charged incorrectly on at most 2 items is
P(x≤2) = P(x=0) + P(x=1) + P(x=2)
= ₙC
× 
×
=
P(x=0) = ₁₄C₀ ×0.4⁰× 0.6¹⁴ = 7.836 × 10⁻⁴
P(x=1) = ₁₄C₁ ×0.4¹× 0.6¹³ = 7.314 × 10⁻³
P(x=2) = ₁₄C₂ ×0.4²× 0.6¹² = 3.169 × 10⁻²
∴ P(x≤2) = 7.836 × 10⁻⁴ + 7.314 × 10⁻³ + 3.169 × 10⁻² = 3.979 × 10⁻²
P(x≤2) = 3.979 × 10⁻².
Answer:
F(4) = -3
Step-by-step explanation:
First, you would plug in 4 for x. PEMDAS, so you would multiply -3 and 4, giving you -12. Then add 9, which gives you -3.
Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
Answer:
8
Step-by-step explanation:
Explanation: The GCF of 56 and 64 is 8 , as 8 goes into 56 exactly 7 times and into 64 exactly 8 times. 8(8)+7(8)=8(7+8).
