841 jumping jacks per 4 minutes
![\frac{841~jumping~jacks}{4~minutes}](https://tex.z-dn.net/?f=%20%5Cfrac%7B841~jumping~jacks%7D%7B4~minutes%7D%20%20)
Divide both sides by 4.
![\frac{841}{4} \div \frac{4}{4} = \frac{210.25}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B841%7D%7B4%7D%20%5Cdiv%20%5Cfrac%7B4%7D%7B4%7D%20%3D%20%5Cfrac%7B210.25%7D%7B1%7D%20%20)
Delilah can do 210.25 (or 210) jumping jacks per minute.
The total amount raised is the sum of the amounts raised by the car wash and the dinner. The car wash raised 7c - 18. The dinner raised 6s - 45. We now add the expressions and combine like terms.
7c - 18 + 6s - 45
We need to combine like terms. Like terms are terms that have the same variables and the same exponents on the variables. 7c and 6s are not like terms since c and s are different variables. They cannot be combined together. Plain numbers, like -18 and -45 are lime terms because their variable parts are the same; they both have no variables.
7c - 18 + 6s - 45 =
= 7c + 6s - 18 - 45
= 7c + 6s - 63
Answer: C. 7c + 6s - 63
Answer:
324352
Step-by-step explanation:
Answer:
The price of pretzels in 1975 = $1.80
Step-by-step explanation:
To answer this question we are assuming the steady rate means linear.Let x be the year and y be the price.
We need to find the slope
m = (y2-y1)/(x2-x1)
= (4.80-4.05)/(2015-2005)
=.75/10
= .075
The slope is .075
We can use the point slope form of the equation
y-y1 = m(x-x1)
y-4.80 = .075(x-2015)
Distribute
y - 4.80 = .075x -151.125
Add 4.80 to each side
y - 4.80+4.80 = .075x -151.125+4.80
y = .075 x - 146.325
We want to find out how much pretzels were in 1975. Put in x=1975
y = .075(1975) -146.325
y = 148.125-146.325
y=1.80