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Svetach [21]
3 years ago
12

Write 73 7/80 as a decimal

Mathematics
2 answers:
Vikki [24]3 years ago
8 0
73 7/80 as a decimal will be 73.0875
Grace [21]3 years ago
7 0
73.0875. You put 7/80 into ur calculator and add 73 to it
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draw a tree diagram to determine the sample space Step-by-step explanation:

4 0
3 years ago
indictate which of the following are propositions.For the ones which are propositions, determine the truth value.(a) The integer
Semmy [17]

Answer:

Step-by-step explanation:

When we propose an hypothesis, it is either true or false. The same goes for a proposition.

The required objective here is to determine the truth value in the following proposition.

(a) The integer 24 is prime.

(b) Is the integer 3​15​ even?

(c) The sum of 3 and 4 is 12.

(d) -4 ∈ Ζ

From the first option:

(a) The integer 24 is prime.

The sentence is a proposition but the truth value is FALSE because a prime number is a number that can only be divide by 1 and itself but in the case of 24, Its factors include  1,2,3,4,6,8,12 and 24 which make 24 to falsify the proposition of being  a prime number.

(b) Is the integer 3​15​ even?

This option is not a proposition but rather a question since it has a question mark, however, 315 is an odd number since it is not divisible by 2.

( c)  The sum of 3 and 4 is 12.

This is a proposition and the truth value is FALSE

The sum of 3+4 = 7  ; Hence; 7 ≠ 12

(d)   -4 ∈ Ζ

This is a proposition and the truth value is TRUE.

-4 ∈ Ζ  is read as ( minus four is an integer  (∈)  of Z )

Yes, this is a proposition and its Truth value is TRUE , since  minus four is an integer  (∈)  of Z

6 0
3 years ago
If shape 1 is a scaled copy of shape 2, what angle corresponds to angle C?
GrogVix [38]

Step-by-step explanation:

Angle W is the corresponds as to angle C

6 0
2 years ago
HELP PLEASE! 15 PTS
defon
The answer is 7/10 because the even values are 2,4,6, and the others are 7,8,9,10. Added together, it adds up to 7/10
4 0
4 years ago
Read 2 more answers
A football player is running the length of a 100 yard long football field. For the first part of the field, he runs at a rate of
notka56 [123]

Answer:

\frac{2}{5}th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = \frac{x}{2} seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = \frac{Distance}{Speed}

= \frac{100-x}{4} seconds

Now total time taken by the player can be represented by the equation

\frac{x}{2}+\frac{100-x}{4}=40

Now we can solve this equation for the value of x.

\frac{2x+100-x}{4}=40

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

= \frac{40}{100}

= \frac{2}{5} or 40%

Therefore, \frac{2}{5}th part of the field was covered in second sprint.

5 0
3 years ago
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