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2 years ago

Jessica had -$68 in her account. She then used her credit card to buy a $64 dress. What is her account balance now?

Mathematics

2 answers:

emmainna [20.7K]2 years ago

5 0

Answer:

-$132

Step-by-step explanation:

-68 + -64 = 132

nataly862011 [7]2 years ago

3 0

Answer:

-$132

Step-by-step explanation:

Jessica is already at -$68 which means she's in the negatives.

Her new dress costs $64 so we need to subtract that from what she had in her account.

-$68 - $64 = -$132

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Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

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P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who disagree with the statement = $\frac{1812}{2625}$ = 0.69

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Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

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P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

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Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

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