Answer:
distance between the two second-order minima is 2.8 cm
Explanation:
Given data
distance = 1.60 m
central maximum = 1.40 cm
first-order diffraction minima = 1.40 cm
to find out
distance between the two second-order minima
solution
we know that fringe width = first-order diffraction minima /2
fringe width = 1.40 /2 = 0.7 cm
and
we know fringe width of first order we calculate slit d
β1 = m1λD/d
d = m1λD/β1
and
fringe width of second order
β2 = m2λD/d
β2 = m2λD / ( m1λD/β1 )
β2 = ( m2 / m1 ) β1
we know the two first-order diffraction minima are separated by 1.40 cm
so
y = 2β2 = 2 ( m2 / m1 ) β1
put here value
y = 2 ( 2 / 1 ) 0.7
y = 2.8 cm
so distance between the two second-order minima is 2.8 cm
Answer:
almost 100% positive its B but dont take me up on it
Answer:
plz write your questions in English
Answer:
Depends on the capacity of battery. Mostly our phones flashlight can be used up to 8 to 10hrs continuosly
Explanation:
Capacity of the battery is level to which battery is charged, & amount of current drawn by the flashlight, you can calculate the answer yourself if u know the capacity of that light.
Moreover you can calculate this by using equation,
E =Pt
So, for time
t=E/P
Batteries are rated in Amp hours, like 10 amp hours will supply us 1 amp for 10 hours
2 amps will give us 5 hours
to learn more about lasting of flashlight,
brainly.com/question/13869629?referrer=searchResults
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