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HACTEHA [7]
2 years ago
14

You are asked to calculate how long a new battery will last on a flashlight when the flashlight is turned on. how long should yo

u expect the answer to be?
Physics
1 answer:
valina [46]2 years ago
5 0

Answer:

           Depends on the capacity of battery. Mostly our phones flashlight can be used up to 8 to 10hrs continuosly

Explanation:

Capacity of the battery is level to which battery is charged, &  amount of current drawn by the flashlight, you can calculate the answer yourself if u know the capacity of that light.

Moreover you can calculate this by using equation,

         E =Pt

So, for time

      t=E/P

Batteries are rated in Amp hours, like 10 amp hours will supply us 1 amp for 10 hours

2 amps will give us 5 hours

to learn more about lasting of flashlight,

brainly.com/question/13869629?referrer=searchResults

#SPJ4

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pH measures how acidic or basic a substance is.

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Which of the following choices concerning the net magnetic flux through any enclosed surface is true according to Gauss' law for
11Alexandr11 [23.1K]

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e. The net magnetic flux in this case would be equal to zero.

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here we know that net magnetic flux is the scalar product of magnetic field vector and area vector

so here we have

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What was the direction of the ball’s velocity
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Part of the question is missing. Here it is:

<em>A 72 g autographed baseball slides off of a 1.3 m high table and strikes the floor a horizontal distance of 0.7m away from the table.     The acceleration of gravity is 9.81 m/s2. What was the direction of the ball’s velocity  just before it hit the floor? </em>

Answer:

\theta=-75.7^{\circ}

Explanation:

The motion of the ball is a projectile motion, which consists of two separate motions:

- A horizontal motion at constant velocity

- A vertical motion at constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time of flight of the ball. This can be done by using the suvat equation

s=ut+\frac{1}{2}at^2

where, choosing downward as positive direction:

s =1.3 m is the vertical displacement of the ball

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time

Solving for t,

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(1.3)}{9.8}}=0.52 s

Now we can find the final vertical velocity of the ball, using:

v_y=u+at

And susbtituting t = 0.52 s, we find

v_y = 0 +(9.8)(0.52)=5.1 m/s

It is important to keep in mind that the direction of this velocity is downward, since we chose downward as positive direction.

The horizontal velocity of the ball instead is constant; we know that the ball covers a horizontal distance of

d = 0.7 m

In a time of

t = 0.52 s

So, the horizontal velocity is

v_x = \frac{0.7}{0.52}=1.3 m/s

So now we can find the direction of the ball's velocity using:

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{5.1}{1.3})=75.7^{\circ}

And since the vertical direction is downward, this means that this velocity is below the horizontal, so the answer is

\theta=-75.7^{\circ}

8 0
3 years ago
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