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HACTEHA [7]
2 years ago
14

You are asked to calculate how long a new battery will last on a flashlight when the flashlight is turned on. how long should yo

u expect the answer to be?
Physics
1 answer:
valina [46]2 years ago
5 0

Answer:

           Depends on the capacity of battery. Mostly our phones flashlight can be used up to 8 to 10hrs continuosly

Explanation:

Capacity of the battery is level to which battery is charged, &  amount of current drawn by the flashlight, you can calculate the answer yourself if u know the capacity of that light.

Moreover you can calculate this by using equation,

         E =Pt

So, for time

      t=E/P

Batteries are rated in Amp hours, like 10 amp hours will supply us 1 amp for 10 hours

2 amps will give us 5 hours

to learn more about lasting of flashlight,

brainly.com/question/13869629?referrer=searchResults

#SPJ4

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All diseases can be prevented.<br><br> A) True or B) False
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B. false is the answer.
8 0
3 years ago
Read 2 more answers
I need some help with this,, anyone??<br>It's has three parts so... (9A), (9B), and (9C)
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A is 588N.

b) When she reaches her terminal speed, 10 seconds into the dive, she is no longer accelerating, so the net force on her is zero.
Think of it this way: If the net force were not zero she would continue to accelerate.

c) She is no longer accelerating.
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3 years ago
Which of the following choices concerning the net magnetic flux through any enclosed surface is true according to Gauss' law for
11Alexandr11 [23.1K]

Answer:

e. The net magnetic flux in this case would be equal to zero.

Explanation:

As per Gauss law of magnetism we need to find the net magnetic flux through a closed loop

here we know that net magnetic flux is the scalar product of magnetic field vector and area vector

so here we have

\int B. dA = net magnetic flux

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then in that case the value of the close integral must be zero

so correct answer would be

e. The net magnetic flux in this case would be equal to zero.

6 0
3 years ago
An accelerating voltage of 2.42 103 V is applied to an electron gun, producing a beam of electrons originally traveling horizont
Pavlova-9 [17]

Answer:

Part (a)  The magnitude of the deflection of electron beam on the screen due to the Earth's gravitational field is 5.97*10^{-16}m.

Part (b) The magnitude of the deflection of electron beam on the screen due to the vertical component of the Earth's magnetic field is 6.19* 10^-3m

 

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3 years ago
If the detector readings are proportional to the amplitude of the microwave E field, the data from the first polarization experi
ololo11 [35]

Answer:

Fields and variables are proportional

Explanation:

To solve the problem we must first identify the Vector Intensity,

The intensity is given by:

I = I_ {0} cos^2 (\theta)

We also know that the change given by the Intensity is always the square of the amplitude,

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That is to say that in turn the amplitus is <em>proportional</em> to the Intensity.

On the other hand, relating the two variables we have

A ^ 2 = A ^ 2_ {0} cos ^ 2 \theta

A = A_ {0} cos \theta

In this way we can conclude that the electric field of intensity is also <em>proportional</em> to cos ^ 2 \theta

7 0
3 years ago
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