Answer:
42 m
Explanation:
= initial velocity of the car = 24 m/s
= final velocity of the car = 0 m/s
μ = coefficient of kinetic friction = 0.7
g = acceleration due to gravity = 9.8 m/s²
a = acceleration due to kinetic frictional force = - μg = - (0.7)(9.8) = - 6.86 m/s²
d = distance through which the car skids
Using the kinematics equation
Inserting the values
d = 42 m
Answer:
The high-leg voltage is
Explanation:
A diagram showing the arrangement of this three phase transformer is shown on the first uploaded image
The high - leg terminal is in the diagram is from
Generally the high-leg terminal is 1.732 times of the the voltage from line to center tap which is given as 277 V
The high -voltage can be computed as follows
Answer:
311,850 N
Explanation:
We can solve the problem by using Newton's second law:
where
F is the net force exerted on the object
m is the mass of the object
a is the acceleration
In this problem, we have
m = 27 kg is the mass
a = 11,550 m/s^2 is the acceleration
Solving for F, we find:
Answer:
63N, 45N
Explanation:
Given:
Tension 1 = T1
We have the following free body equations:
F - T1 = 100*0.3 -(I)
T1 - T2 = 60*0.3 -(II)
T2 = 150*0.3 -(III)
Adding the three above equations, we have
F - T1 + T1 - T2 + T2 = (100*0.3) + (60*0.3) + (150*0.3)
Hence, F = 93N
Hence, substituting into equation I we have
T1 = Force by bar on lighter cart = 93 - (100*0.3) = 63N
Hence, force that heavier cart exerts on bar
T2 = 150*0.3 = 45N
Let's assume that the pressure given is 771 torr.
Answer:
747.44 torr
Explanation:
The eudiometer tube is a setup that collects gas in a liquid (generally water). After the thermal equilibrium, the gas becomes in equilibrium with the vapor of water above the liquid.
By Dalton's law, the total pressure of a mixture is the sum of the partial pressure of its components. The partial pressure is the pressure that the gas would have at the same conditions if it was alone. So, the pressure of the dry gas is its partial pressure.
The total pressure is the barometric pressure, and the partial pressure of the water vapor at 20°C is 23.56 torr (the value can be found at a thermodynamic table). So, the pressure of the dry gas (P) is:
771 = 23.56 + P
P = 771 - 23.56
P = 747.44 torr