gravitational force between two objects is given as
F = G m₁ m₂/r²
where m₁ = mass of first object , m₂ = mass of second object , r = distance between the two objects .
Initial case :
m₁ = m₂ = m
gravitational force between the objects is given as
F = G m²/r²
Final Case :
m₁ = m₂ = 3 m
new gravitational force between the objects is given as
F' = G (3m)²/r²
F' = 9 G m²/r²
F' = 9 F
hence the gravitational force between the two objects becomes 9 times.
k= - f/x this is the formula for spring constants
Answer:
a = 2.72 [m/s2]
Explanation:
To solve this problem we must use the following kinematics equation:

where:
Vf = final velocity = 1200 [km/h]
Vo = initial velocity = 25 [km/h]
t = time = 2 [min] = 2/60 = 0.0333 [h]
1200 = 25 + (a*0.0333)
a = 35250.35 [km/h2]
if we convert these units to units of meters per second squared
![35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]](https://tex.z-dn.net/?f=35250.35%5B%5Cfrac%7Bkm%7D%7Bh%5E%7B2%7D%20%7D%5D%2A%28%5Cfrac%7B1%7D%7B3600%5E%7B2%7D%20%7D%29%2A%5B%5Cfrac%7Bh%5E%7B2%7D%20%7D%7Bs%5E%7B2%7D%20%7D%20%5D%2A%28%5Cfrac%7B1000%7D%7B1%7D%20%29%2A%5B%5Cfrac%7Bm%7D%7Bkm%7D%20%5D%20%3D%202.72%20%5B%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D%20%5D)