All categories

3 years ago

How does the polarity of the solute affect how well a solvent will dissolve?

1 answer:

4 0

Polarity is the ability to distinguish between the electric charge of a molecule or different chemical groups having dipoles or multipole moment. Polar molecules have polar bonds based on the difference in electronegativity between atoms bonded together. Polarity affects how solvents dissolve by following the idea that "like dissolves like" in other words, polar molecules are best dissolved in polar solvents and nonpolar molecules dissolve better in nonpolar solvents. Moreover, ionic solvents dissolve polar solutes. By this the final answer is E, similar polarity makes the solvent more likely to dissolve

You might be interested in

Write the balanced nuclear equation for β− decay of silicon−32. Include both the mass numbers and the atomic numbers with each n

weqwewe [10]

Answer:

$^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e$

Explanation:

Beta decay conserves the lepton number. In $\beta^-$ decay, the atomic number of the element increases which is accompanied by the release of an electron antineutrino, $e^-+\bar{v}_e$ .

For example:-

$^A_ZX\rightarrow ^A_{Z+1}X+e^-+\bar{v}_e$

The $\beta^-$ decay of silicon-32 is shown below as:-

$^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e$

8 0

3 years ago

Periodic table, chemistry questions

ehidna [41]

Answer:

Explanation:

The Lanthanides were first discovered in 1787 when a unusual black mineral was found in Ytterby, Sweden. This mineral, now known as Gadolinite, was later separated into the various Lanthanide elements. In 1794, Professor Gadolin obtained yttria, an impure form of yttrium oxide, from the mineral.

7 0

3 years ago

It takes 60 mL of 0.20 M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H2CO3) for the following chemical reac

irina1246 [14]

If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid ( $H_2CO_3$ ), then the concentration of the carbonic acid is 0.24M

The reaction between NaOH solution and $H_2CO_3$ is written below

$2NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2H_2O$

Volume of NaOH, $V_B$ = 60 ml

Volume of $H_2CO_3$ , $V_A=25 ml$

Molarity of $H_2CO_3$ , $C_A=?$

Molarity of NaOH, $C_B=0.20M$

Number of moles of $H_2CO_3$ , $n_A=1$

Number of moles of NaOH, $n_B=2$

The mathematical equation for neutralization reaction is:

$\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}$

Substitute $C_B=0.2 M$ , $n_A=1$ , $n_B=2$ , $V_B$ = 60ml, and $V_A=25 ml$ into the equation above in order to solve for $C_A$

$\frac{C_A \times 25}{0.2 \times 60}=\frac{1}{2} \\\\50C_A=12\\\\C_B=\frac{12}{50} \\\\C_B=0.24M$

Therefore, the concentration of the carbonic acid is 0.24M

Learn more here: brainly.com/question/25943090

3 0

1 year ago

When you divide the mass of a substance by its volume, you get its.

Zarrin [17]

Answer:Density

Explanation:

8 0

2 years ago

Read 2 more answers

What must be conserved in a balanced nuclear equation?

Law Incorporation [45]

There is nothing conserved<span> in this reaction. When writing a β </span>equation<span>, remember that in the nucleus, a neutron ( n ) decays into a proton ( p+ ) and a high energy electron which is known as the beta ( β ) particle. Because a new proton has formed, the atomic number of the original atom will increase by 1</span>

5 0

3 years ago