First, we will get the "n", the number of half lives, it is the elapsed time over the half life. In the problem, the time is measured in days, so we have
6/2 = 3
to get the ending amount of radioactive sample, we have
32g x (1/2)³ = 4 grams of radioactive sample ⇒ the amount left after 6 days
Answer:
5
Explanation:
mass number=no of protons +no of neutron
mass number-atomic number=no of neutron
12-7=5
Complete Question
The complete question is shown on the first uploaded image
Answer:
The pressure is ![[O_2] = 4.8 *10^{-5} \ atm](https://tex.z-dn.net/?f=%5BO_2%5D%20%3D%20%204.8%20%2A10%5E%7B-5%7D%20%5C%20atm)
Explanation:
From the question we are told that
The pressure of
is ![[SO_3 ] = 0.63 \ atm](https://tex.z-dn.net/?f=%5BSO_3%20%5D%20%3D%20%200.63%20%5C%20atm)
The pressure of
is ![[SO_ 2] = 0.30 \ atm](https://tex.z-dn.net/?f=%5BSO_%202%5D%20%20%3D%20%200.30%20%5C%20atm)
The equilibrium constant is
The reaction is
⇔ 
Generally the equilibrium constant is mathematically represented as

=> ![[O_2] = \frac{k_p * [SO_3] ^2 }{[SO_2]^2}](https://tex.z-dn.net/?f=%5BO_2%5D%20%3D%20%20%5Cfrac%7Bk_p%20%2A%20%5BSO_3%5D%20%5E2%20%7D%7B%5BSO_2%5D%5E2%7D)
substituting values
![[O_2] = \frac{1.2 *10^{-5} * 0.60 ^2 }{0.30^2}](https://tex.z-dn.net/?f=%5BO_2%5D%20%3D%20%20%5Cfrac%7B1.2%20%2A10%5E%7B-5%7D%20%2A%200.60%20%5E2%20%7D%7B0.30%5E2%7D)
![[O_2] = 4.8 *10^{-5} \ atm](https://tex.z-dn.net/?f=%5BO_2%5D%20%3D%20%204.8%20%2A10%5E%7B-5%7D%20%5C%20atm)
Answer:
See the explanation below
Explanation:
Both the cup of coffee and drop of coffee have the Same temperature of 95°C.
Although the difference is the cup of coffee has more heat contained in it than the drop of coffee. An explanation is when we heat a cup of coffee it will take more time to Attain in 95°C while the drop of coffee will take less time