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3 years ago

What is the frequency of light for which the wavelength is 7.1 × 102 nm?

Chemistry

1 answer:

ludmilkaskok [199]3 years ago

4 0

Answer:

4.2 × 10⁻¹⁴s⁻¹

Explanation:

Given parameters:

Wavelength of light = 7.1 x 10²nm

We simplify and express this value in metres(m) to give:

⇒7.1 x 10² x 10⁻⁹m = 7.1 x 10⁽⁻²⁺⁹⁾ m

= 7.1 x 10⁷m

The wavelength is 7.1 x 10⁷m

We use the formula V = fλ

We know that Velocity of light is 3 x 10⁸ms⁻¹

Making f, frequency the subject of the formula gives :

f = V/λ

f = 3 x 10⁸ms⁻¹ / 7.1 x 10⁷m

f = 4.2 x 10⁻¹⁴s⁻¹

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Serga [27]

Explanation:

$Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}$

Mass of NaOH = m

MOlar mass of NaOH = 40 g/mol

Volume of NaOH solution = 1.00 L

Molarity of the solution= 1.00 M

$1.00 M=\frac{m}{40 g/mol\times 1.00 L}$

$m=1.00 M\times 40 g/mol\times 1.00 L = 40. g$

A student can prepare the solution by dissolving the 40. grams of NaOH in is small volume of water and making that whole volume of solution to volume of 1 L.

Upto two significant figures mass should be determined.

$M_1V_1=M_2V_2$ (dilution equation)

Molarity of the NaOH solution = $M_1=2.00 M$

Volume of the solution = $V_1=?$

Molarity of the NaOH solution after dilution = $M_2=1.00 M$

Volume of NaOH solution after dilution= $V_2=1 L$

$M_1V_1=M_2V_2$

$V_1=\frac{1.00 M\times 1.00 L}{2.00 M}=0.500 L$

A student can prepare NaOH solution of 1.00 M by diluting the 0.500 L of 2.00 M solution of NaOH with water to 1.00 L volume.

Upto three significant figures volume should be determined.

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3 years ago

Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma

Katen [24]

Answer: 12.0 milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn.

Explanation:

moles = $\frac{\text {given mass}}{\text {Molar mass}}$

moles of zinc = $\frac{2.55g}{65.38g/mol}=0.0390moles$

The balanced chemical equation is :

$Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)$

According to stoichiometry:

1 mole of zinc reacts with = 2 moles of HCl

Thus 0.0390 moles of zinc reacts with = $\frac{2}{1}\times 0.0390=0.0780$ moles of HCl

To calculate the volume for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}$ .....(1)

Molarity of $HCl$ solution = 6.50 M

Volume of solution = ?

Putting values in equation 1, we get:

$6.50M=\frac{0.0780\times 1000}{\text{Volume of solution in ml}}$

${\text{Volume of solution in ml}}=12.0ml$

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3 years ago

What is the molarity of a solution that contains 0.220 moles KOH in 0.350 L of solution?

Lera25 [3.4K]

Answer:

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In order to solve this problem we need to keep in mind the definition of molarity:

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We are given both the number of moles and the volume of solution, meaning we can now proceed to calculate the molarity:

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