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Leto [7]
3 years ago
11

The rising of cold water from deeper layers to replace warmer surface is called

Chemistry
2 answers:
Xelga [282]3 years ago
7 0
Upwelling is the answer
KatRina [158]3 years ago
6 0

C) Upwelling

<em>- Prodixy</em>

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The temperature at which a substance in the liquid phase transforms to the gaseous phase refers to the substance's _______. A. s
murzikaleks [220]
When a substance goes from being a liquid to a gas it evaporates, or boils away. Think of boiled eggs.
3 0
3 years ago
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Implement pollution reduction strategies that are needed to clean up the river ????
miss Akunina [59]

Answer:

*  Properly dispose of hazardous household items.

*  Reduce or eliminate use of fertilizers and chemical herbicides and           pesticides.

*  Make an appointment to service your septic system

Landscape with native plants.

*  Eliminate bare spots in your yard.

*  Make a rain garden.

WAS THIS HELPFUL......

8 0
1 year ago
What is the volume in (a) liters and (b) cubic yards of a room that is 10. meters wide by 15 meters long and 8.0 ft high?
deff fn [24]

Answer:

V = 364500 L, 476.748 yard³

Explanation:

Given that,

The dimensions of a room are 10 meters wide by 15 meters long and 8.0 ft high.

l = 10 m, b = 15 m, h = 8 ft = 2.43 m

The volume of the room is :

V = lbh

So,

V = 10×15×2.43

V = 364.5 m³

As 1 m³ = 1000 L

364.5 m³ = 364500 L

Also, 1 m³ = 1.30795 yard³

364.5 m³ = 476.748 yard³

Hence, this is the required solution.

7 0
2 years ago
What volume and mass of steam at 100 Celsius and 760. torr (or 1 atm) would release the same amount of energy as heat during con
erastova [34]
  
<span>As we know that
1 cu cm H2O = 1 mL H2O = 1g H2O 
now

Heat of fusion of water = 79.8 cal/g 
and

Heat of vaporization of water = 540 cal/g 

Atomic weight of water : H=1 O=16 H2O=18 
now by calculating and putting values

65.5gH2O x 79.8cal/gH2O x 1gH2O/540cal = 9.68g H2O (steam) 

9.68gH2O x 1molH2O/18gH2O x 22.4LH2O/1molH2O = 12.0 L H2O
hope it helps</span>
3 0
3 years ago
Read 2 more answers
What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l
Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law:  PV=nRT where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units:R=0.0821\frac{L\cdot atm}{mol\cdot K}

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means T=273.15K and P=1atm

Lastly, we must calculate the number of moles of O_2(g) there are.  Given 0.80g of O_2(g), we will need to convert with the molar mass of O_2(g).  Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2:  32g\text{ }O_2=1mol\text{ }O_2

Thus, \frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n

Isolating V in the Ideal Gas Law:

PV=nRT

V=\frac{nRT}{P}

...substituting the known values, and simplifying...

V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}

V=0.56L \text{ } O_2

So, 0.80g of O_2(g) would occupy 0.56L at STP.

5 0
2 years ago
Read 2 more answers
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