Answer:
Q = -3980.9 j
Explanation:
Given data:
Mass of sample = 30 g
Initial temperature = 56.7 °C
Final temperature = 25 °C
Specific heat of water = 4.186 j/g.°C
Amount of heat released = ?
Formula:
Q = m.c.ΔT
Q = heat released
m = mass of sample
c = specific heat of given sample
ΔT = change in temperature
Solution:
ΔT = T2 -T1
ΔT = 25 °C - 56.7 °C = - 31.7°C
Q = m.c.ΔT
Q = 30 g × 4.186 j/g.°C × - 31.7°C
Q = -3980.9 j
Answer:
"hydrogen to oxygen"
Explanation:
Hydrogen bonds are formed when hydrogen is bonded to highly electronegative element such as Chlorine, fluorine, oxygen etc.
In hydrogen bonding, the hydrogen atom of one molecule of water is attracted to the oxygen atom of another molecule of water via permanent dipole-dipole interaction.
Hence, If you have 2 water molecules together, they always sit "hydrogen to oxygen" as a result of dipole - dipole interaction and hydrogen bonding between water molecules.
Answer:
D.) 2 H₂ + O₂ -----> 2 H₂O
Explanation:
An equation is balanced when there is an equal amount of each element on both sides of the reaction. If these amounts are unequal, coefficients can be added to modify the amount of particular molecules.
A.) Not balanced
2 H₂ + 2 O₂ -----> H₂O
<u>Reactants</u>: 4 hydrogen, 4 oxygen
<u>Products</u>: 2 hydrogen, 1 oxygen
B.) Not balanced
2 H₂ + 2 O₂ -----> 2 H₂O
<u>Reactants</u>: 4 hydrogen, 4 oxygen
<u>Products</u>: 4 hydrogen, 2 oxygen
C.) Not balanced
H₂ + O₂ -----> H₂O
<u>Reactants</u>: 2 hydrogen, 2 oxygen
<u>Products</u>: 2 hydrogen, 1 oxygen
D.) Balanced
2 H₂ + O₂ -----> 2 H₂O
<u>Reactants</u>: 4 hydrogen, 2 oxygen
<u>Products</u>: 4 hydrogen, 2 oxygen
