It is supposed to protect the cell from it's surroundings, or from the outside.
Answer:
The correct answer is option c.
Explanation:
Alkanes with higher molecular mass has higher boiling point.
Thisis because when the molar mass of the alkanes increases the the surface area increases with which van der Waals forces between the molecules of alkane also increase which increases the association of the molecules of with each other which results in increase in boiling point is observed.
The increasing order of the molar mass of the given alkanes;
So out of ethane, pentane and heptane . Heptane has highest molecular mass with higher boiling point value. Where as ethane have the lowest value of boiling point.
Answer:
We would need 10 mL of the concentrated CaCl₂ stock solution, and 30 mL of water.
Explanation:
To solve the question asked we can use the C₁V₁=C₂V₂ equation, where:
We <u>solve for V₁</u>:
We would need 10 mL of the concentrated CaCl₂ stock solution, and (40-10) 30 mL of water.
To figure this out, you need to figure out how many molecules of mgso4 you have.
If you have 1.04 moles of MgSO4, you have that many moles times avogadro's number (6.022*10^23 molecules/mole).
1.04 moles MgSO4 * (6.022*10^23 molecules MgSO4)/1 mole MgSO4 =
6.263 *10^23 molecules MgSO4
Next, there are 4 oxygen atoms per molecule of MgSO4, so we multiply the number of molecules of MgSO4 by 4 to get the number of oxygen atoms.
6.263 *10^23 molecules MgSO4 * (4 oxygen atoms/1 MgSO4 molecule) = 2.51 * 10^24 oxygen atoms in 1.04 moles of MgSO4
