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Paladinen [302]
2 years ago
7

How would one convert 15 seconds to hours?

Chemistry
2 answers:
Tju [1.3M]2 years ago
8 0

Answer:

answer d

Explanation:

kodGreya [7K]2 years ago
5 0

Answer:

A

Explanation:

15 sec   *   1 hr/3600 sec    (note how 'sec'  cancels out and you are left with 'hour' in your answer)   =    15/3600 hour

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What substance has a melting point of 0 and a boiling point of 100
tiny-mole [99]

Answer:

Water

Explanation:

Water molecules are known to have a melting point of 0°C and a boiling point of 100°C.

The melting and boiling points are as a result of the intermolecular force of attraction between the molecules of water. The predominant bond type that dictates the property of the melting and boiling point is the hydrogen bonding. This bond is a strong force of attraction and it impacts on the physical properties of water.

7 0
3 years ago
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What is a Product? ASAP
Masja [62]

Answer:

Do you want me to give you the definition in math, science or just what a product means because there's different types.

3 0
3 years ago
CH3CN major species present when dissolved in water
Margaret [11]

Answer: CH₃CN and H₂O.

Explanation:

1) The spieces present in a solution may be either the molecules, in case of covalent compounds, or ions, in case of ionic compounds that dissociate (ionize).

2) Both, CH₃CN and H₂O are covalent (polar covalent) substances, so they do not ionize and the spieces in the solution are the molecules per se.

3) In solution, the molecules of H₂O will solvate the molecules of CH₃CN, meaning that H₂O molecules are able to separate the molecules of CH₃N from each other, and so every molecule of CH₃CN will end surrounded by many molecules of H₂O.

This happens because the interaction between the polar molecules of the two different compounds is strong enough to overcome the intermolecular forces between the molecules of the same compound.

3 0
3 years ago
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Consider a mixture of two gases, A and B, confined in a closed vessel. A quantity of a third gas, C, is added to the same vessel
n200080 [17]

The question is incomplete, here is the complete question:

Consider a mixture of two gases, A and B, confined in a closed vessel. A quantity of a third gas, C, is added to the same vessel at the same temperature. How does the addition of gas C affect the following. The mole fraction of gas B?

A mixture of gases contains 10.25 g of N₂, 2.05 g of H₂, and 7.63 g of NH₃.

<u>Answer:</u> The mole fraction of gas B (hydrogen gas) is 0.557

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For nitrogen gas:</u>

Given mass of nitrogen gas = 10.25 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen gas}=\frac{10.25g}{28g/mol}=0.366mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 2.05 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen gas}=\frac{2.05g}{2g/mol}=1.025mol

  • <u>For ammonia gas:</u>

Given mass of ammonia gas = 7.63 g

Molar mass of ammonia gas = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia gas}=\frac{7.63g}{17g/mol}=0.449mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B+n_C}

Moles of gas B (hydrogen gas) = 1.025 moles

Total moles = [0.366 + 1.025 + 0.449] = 1.84 moles

Putting values in above equation, we get:

\chi_{(H_2)}=\frac{1.025}{1.84}=0.557

Hence, the mole fraction of gas B (hydrogen gas) is 0.557

6 0
3 years ago
A 20.0 mL sample of a NaCl solution has a mass of 21.040g. After the solution is evaporated to dryness, the dry salt residue has
Vilka [71]
Mass NaCl = 4.348
Mass solution = 21.040 - 4.348 = 16.692
mass/mass % =
4.348/16.692
= 26%
mass/vol % =
21.7%
Molecular mass of NaCl = 58.5
Moles of NaCl = 0.074
Volume of solution = 0.02 L
Molarity = 3.7 mol/Liter
7 0
4 years ago
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