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Paladinen [302]
2 years ago
7

How would one convert 15 seconds to hours?

Chemistry
2 answers:
Tju [1.3M]2 years ago
8 0

Answer:

answer d

Explanation:

kodGreya [7K]2 years ago
5 0

Answer:

A

Explanation:

15 sec   *   1 hr/3600 sec    (note how 'sec'  cancels out and you are left with 'hour' in your answer)   =    15/3600 hour

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In the diagram, which letter represents the transition from liquid to gas?<br> B<br> A<br> D<br> C
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I got on here because I don't understand the question but I did my best to answer because I noticed you asked 3 days ago. IF I'm right the answer is D. My diagram shows
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3 years ago
What is atomic?................................................
Pavel [41]

Answer:

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3 years ago
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Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---&gt; C2H2(g) ΔH° = ??? kJ Given the following thermochemical equation
nordsb [41]

Answer:

The enthalpy for given reaction is 232 kilo Joules.

Explanation:

C_2H_2(g) + \frac{5}{2}O_2(g)\rightarrow 2CO_2(g) + H_2O(l), \Delta H^o_{1} = -1,123 kJ...[1]

C(s) + O_2(g)\rightarrow CO2(g), \Delta H^o_{2} = -340 kJ..[2]

H_2(g) + \frac{1}{2}O_2(g)\rightarrow H_2O(l) ,\Delta H^o_{3} = -211 kJ..[3]

2C(s) + H_2(g)\rightarrow C_2H_2(g),\Delta H^o_{4} =?..[4]

2 × [2] + [3] - [1] ( Using Hess's law)

\Delta H^o_{4}=2\times \Delta H^o_{2}+\Delta H^o_{3} - \Delta H^o_{1}

\Delta H^o_{4}=2\times (-340 kJ) + (-211 kJ) - (-1,123 kJ)

\Delta H^o_{4}=232 kJ

The enthalpy for given reaction is 232 kilo Joules.

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3 years ago
What is the relationship between the reactant and yield
solong [7]
Yield is the measured amount of a product obtained from a reaction.

Hope that's helpful
7 0
3 years ago
The central core of an atom is called the __?
PilotLPTM [1.2K]

Answer: Atomic Nucleus!

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(Yes, it was from google.)

6 0
3 years ago
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