Answer:
<h3>6 days</h3>
Step-by-step explanation:
Given the inequality expression of the total cost (c) in dollars of renting a car for n days as c ≥ 125 + 50n
To get the maximum number of days for which a car could be rented if the total cost was $425, substitute c = 425 into the expression and find n
425 ≥ 125 + 50n
Subtract 125 from both sides
425 - 125 ≥ 125 + 50n - 125
300≥ 50n
Divide both sides by 50
300/50≥50n/50
6 ≥n
Rearrange
n≤6
<em>Hence the maximum number of days for which a car could be rented if the total cost was $425 is 6days</em>
<em></em>
Step-by-step explanation:
1. simple interest
I= p × r × t
I = 1050 × 4.5 × 2
I = $9450
2. principal
p = I/(rt)
p= 22.50/ (3× 3)
p = 22.50/9
p = $2.5
3. simple interest
I= p × r × t
I = 500 × 5 × 3
I = $7500
4. time
first convert r to decimal
r= r/100, r= 3.5 / 100
r= 0.035
t = i/(pr)
t = 43.75/ (2500× 0.035)
t = 43.75/ 87.5
t = 0.5 year or 6 months
Answer:
55,98,27
Step-by-step explanation:
To solve for the angles we must first find y with this equation
3y+5+2y-7=153
We can simplify this
5y-2=153
153+2=155
155/5=31
y=31
We now know y and can plug it into the angles
<A=2y-7
2(31)-7
62-7
55
<A=55
<B=3y+5
3(31)+5
93+5
98
<B=98
Now time for the last angle
Since angle BCA and DCB are next to each other they add up to 180
153+x=180
180-153=27
x=27
<BCA=27
