All categories

3 years ago

9 – 2k = 25 what is k

Mathematics

2 answers:

worty [1.4K]3 years ago

8 0

Answer:

k = - 8

Step-by-step explanation:

Subtract 9 from both sides to get the constants on one side and the variables on the other

9 - 2k = 25

- 2k = 25 - 9

Simplify

- 2k = 16

Divide by -2 on both sides to isolate the variable, then simplify once more.

- 2k/ -2 = 16/ -2

k = 16/ -2

k = -8

Gnom [1K]3 years ago

7 0

Answer:

k = -8

Step-by-step explanation:

9 – 2k = 25

- 2k = 25 - 9

-2k = 16

k = 16 / -2

k = -8

You might be interested in

What's the square root of 1/36?

stich3 [128]

0.27... repeating :)

6 0

3 years ago

Need help with this question -9×3-4^2/ 3^2 + 2^2

Vesnalui [34]

-9 × 3 - 4² = -27 - 16 = -43

3² + 2² = 9 + 4 = 13

(-9 × 3 - 4²)/(3² + 2²) = -43/13 = -3 4/13

3 0

3 years ago

EACH PAIR OF FIGURES IS SIMILAR. FIND THE MISSING SIDE!!!!

inessss [21]

Answer:

58.1 and 17

Step-by-step explanation:

For the first triangles the similarity ratio is 1:7 so x is 8.3 × 7 = 58.1

For the second triangles the similarity ratio is 1:5 so x is 3.4 × 5 = 17

8 0

3 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

A small business produces and sells balls. The fixed costs are $20 and each ball costs $4.32 to produce. Each ball sells for $8.

Gemiola [76]

Part 1:

Fixed Cost, f = $20

number of balls = n

Cost of each ball, c = 4.32

Price of each ball, p = 8.32

Equation for total cost:

Total Cost of balls will come by adding the cost of all balls and the fixed cost

Total Cost = number of balls made × Cost of each ball + fixed cost

Equation for revenue:

Revenue = Number of balls made × price of each ball

Part 2:

Use the graphing method to determine how many balls must be sold to break even

Breakeven means Revenue = total Cost

This happens at a point (5,41.6) where n = 5 is the number of balls sold

and C = 41.6 is the total cost

When 5 balls are sold there will be breakeven

R = 4n - 20

C = 4.32n + 20

Red line represent Cost

Black line represent Revenue

5 0

3 years ago