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3 years ago

9 – 2k = 25 what is k

Mathematics

2 answers:

worty [1.4K]3 years ago

8 0

Answer:

k = - 8

Step-by-step explanation:

Subtract 9 from both sides to get the constants on one side and the variables on the other

9 - 2k = 25

- 2k = 25 - 9

Simplify

- 2k = 16

Divide by -2 on both sides to isolate the variable, then simplify once more.

- 2k/ -2 = 16/ -2

k = 16/ -2

k = -8

Gnom [1K]3 years ago

7 0

Answer:

k = -8

Step-by-step explanation:

9 – 2k = 25

- 2k = 25 - 9

-2k = 16

k = 16 / -2

k = -8

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Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima

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Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

$\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416$

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