All categories

3 years ago

Write 368% as a mixed number.

Mathematics

1 answer:

Allushta [10]3 years ago

8 0

Answer:

$3\frac{17}{25}$

Step-by-step explanation:

368%

convert to a fraction

$\frac{368}{100}$

divide top and bottom by 2

$\frac{184}{50}$

divide top and bottom by 2

$\frac{92}{25}$

92/25 = 3 remainder 17

$3\frac{17}{25}$

You might be interested in

The selling price of an item is $ 440 After 6 months of not selling, it is marked down by 30%. After another 6 months of not

liq [111]

440...marked down by 30% means u pay 70%
70% of 440 = 0.70(440) = 308

308 ..marked down by 10% means u pay 90%
90% of 308 = 0.90(308) = 277.20 <== price after markdowns

8 0

3 years ago

Cevabını yazarmısınız

Anit [1.1K]

Answer:

it is side ways

Step-by-step explanation:

6 0

3 years ago

Equation for line passing through (4,3) perpendicular to y=5x+4

ehidna [41]

Perpendicular to the line y = 5x - 9

m= -1/5

the line passing through the point (1, 4):

4=-1/5*1+q
q= 21/5

the equation is:
y= -1/5x +21/5
or
x+5y-21=0

5 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

–10 = –6 + 2c –8 1 –2 2

guapka [62]

–10 = –6 + 2c

+ 6 + 6 Add 6 to cancel out -6

-4 = 2c

/2 /2 Divide by 2 to get c variable alone

-2 = c Choice C is the correct answer

6 0

3 years ago