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bixtya [17]
3 years ago
5

A photon has 8.0 × 10–15 J of energy. Planck’s constant is 6.63 × 10–34 J•s.

Chemistry
1 answer:
NISA [10]3 years ago
7 0
The frequency of a photon with an energy of 8.0 × 10⁻¹⁵ J is  1.21 × 10¹⁹  /s.

How to arrived at the answer is attached below

Please note that v= frequency; h= Plank's constant; E= Energy

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How long will it take Barium-142 to decay to 25% of its original size?
Leya [2.2K]

Answer:

5.68

Explanation:

just divide. hope this helps!

6 0
3 years ago
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5. Citric acid is the main acid present in lemon juice. However vitamin C, or ascorbic acid is
aev [14]

In the titration of lemon juice, the presence of ascorbic acid means the concentration of citric acid you calculated is higher.

An acid-base titration is a common way to determine the unknown concentration of an acid, given we know the concentration of the base and determine the spent volume in the titration. Let's consider the neutralization reactions that take place in a mixture of citric acid and ascorbic acid.

Citric acid titration :

3 NaOH(aq)  +  H₃C₆H₅O₇(aq)  →  Na₃C₆H₅O₇(aq)  +  3 H₂O(l)

Ascorbic acid titration:

NaOH(aq) + HC₆H₇O₆(aq)  →   NaC₆H₇O₆(aq)   +  H₂O(l)

If we titrated a solution that contained only citric acid, we can relate through stoichiometry the moles and concentration of citric acid. However, if the solution also contained ascorbic acid, we would have to spend more NaOH to titrate it. Since more NaOH would react, we would conclude that there is more citric acid to react, calculating a higher concentration of the same.

In the titration of lemon juice, the presence of ascorbic acid means the concentration of citric acid you calculated is higher.

You can learn more about titration here: brainly.com/question/2728613

7 0
2 years ago
Please hurry I’m stuck!!
MakcuM [25]

Answer:

B

Explanation:

C+O2=CO2

5 0
3 years ago
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How can an atom create charge
irga5000 [103]

Answer:

When the electrons hit the atoms in the chamber, they cause some of the electrons in the atoms to be stripped or knocked away. ... When one or more electrons is knocked off of an atom, it becomes positively charged. It is now an positive ion. A negative ion can be made by adding an electron to an atom.

<em>if </em><em>it </em><em>helped </em><em>then </em><em>plz </em><em>mark </em><em>me </em><em>as </em><em>brainliest </em>

4 0
3 years ago
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How much heat is absorbed when 90.5 g of ice is heated from -11.0 °C to 145.0 °C?
Nadusha1986 [10]

Answer:

Q(total) = 283Kj

Explanation:

5 Heat Transitions …

Specific Heats => c(s) = 0.50cal/g∙⁰C,  c(l) = 1.0 cal/g∙⁰C, c(g) = 0.48 cal/g∙⁰C

Phase Transition Constants => ΔHᵪ = Heat of Fusion = 80 cal/g; ΔHᵥ = Heat of Vaporization = 540cal/g

Note => Phase change regions => no temp. change occurs when 2 phases are in contact (melting and evaporation). Only when single phase substance exists (s, l or g) does temperature change occur. See heating curve for water diagram. The increasing slopes are temperature change regions and heat flow is given by Q =mcΔT. The horizontal slopes are phase changes ( melting & evaporation) and heat flow for each of those regions is given by Q = m·ΔH. Each transition energy is calculated individually (see below) and added to obtain the total heat flow needed.

Q = mcΔT for temperature change regions of the heating curve (single phase only)

Q = m∙ΔH for phase transition regions of the heating curve (2 phases in contact)

Solid (ice) => Melting Pt  => Q(s) = mcΔT = (90.5g)(0.50cal/g∙⁰C)(11⁰C) = 478 cal

Melting (s/l) => Liquid (water) =>   Q(s/l) = m∙ΔHᵪ = (90.5g)(80cal/g) = 7240 cal

Liquid (water) => Boiling Pt => Q(l) = mcΔT = (90.5g)(1.0cal/g∙⁰C)(100⁰C) = 9050 cal

Boiling (l/g) => Gas (steam) => Q(l/g) = m∙ΔHᵥ = (90.5g)(540cal/g) = 48,870 cal

Gas (steam) => Steam @ 145⁰C => Q(g = mcΔT = (90.5g)(0.48cal/g∙⁰C)(45⁰C) = 2036 cal

Total Heat Transfer (Qᵤ) = Q(s) + Q(s/l) + Q(l) + Q(l/g) + Q(g)  

                                 = 478cal +7240cal + 9050 cal + 48,870cal + 2036cal

                                 = 67,674 cal x 4.184 j/cal = 283,148 joules = 283 Kj

4 0
4 years ago
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