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yulyashka [42]
3 years ago
6

The enthalpy of Sodium is 235 calories. The enthalpy Chlorine is 435 calories. The enthalpy of Sodium chloride 670 joules, what

is the change in enthalpy for this reaction?
Chemistry
1 answer:
Anna007 [38]3 years ago
7 0

Answer:

ΔH = -2446J

Explanation:

Based on the reaction:

2 Na(s) + Cl2(g) → 2NaCl

We can find the enthalpy of this reaction using Hess's law:

The enthalpy of a reaction is equal to the sum of the enthalpy of products times their reaction quotient subtracting the enthalpy of reactants times their reaction quotient. For the reaction of the problem:

ΔH = 2ΔH(NaCl) - [2ΔH(Na) + ΔHCl2)]

ΔH(NaCl) = 670J

ΔH(Na) = 235cal * (4.184J/1cal) = 983J

ΔHCl2 = 435cal * (4.184J/1cal) = 1820J

ΔH = 2*670J - [2*983J + 1820J]

ΔH = 1340J - [3786J]

<h3>ΔH = -2446J</h3>
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Answer:

B

Explanation:

It is believed that early humans used the Bering Land Bridge to migrate from Asia to the Americas

Hope this helps! :)

7 0
3 years ago
At STP, which gas sample has a volume of 11.2 liters?
Natasha2012 [34]

Answer:

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

Explanation:

Step 1: Data given

Volume of a gas at STP = 11.2 L

STP: Pressure = 1 atm  and temperature = 273 K

Step 2: Calculate volume

p*V= n*R*T

V = (n*R*T)/p

⇒with V = the volume of the gas = TO BE DETERMINED

⇒with n = the number of moles of the gas

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273 K

⇒with p = the pressure of the gas = 1 atm

A ) 0.250 mole of NH3

V = (0.250 * 0.08206 * 273) / 1

V = 5.6 L

B ) 0.500 mole of CO2

V = (0.500 * 0.08206 * 273) / 1

V = 11.2 L

C ) 0.750 mole of NH3

V = (0.750 * 0.08206 * 273) / 1

V = 16.8 L

D) 1.00 mole of CO2

V = (1.00 * 0.08206* 273) / 1

V = 22.4 L

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

3 0
4 years ago
Why was the morning session stopped unsuccessfully?
Sonbull [250]

Answer:

the reactor was overheating

8 0
3 years ago
What type of energy does most energy end up as
valentinak56 [21]

Answer:

The energy associated with motion ends up as kinetic energy . The energy associated with position ends up as potential energy .

Explanation:

8 0
3 years ago
10. a. What is the binding energy released when an alpha particle of mass 6.64 x 10-27 kg escapes from the nucleus of Uranium- 2
shutvik [7]

Answer:

The binding energy released is 1.992 X 10⁻¹⁸ J

Explanation:

Given;

mass of the alpha particle, m = 6.64 x 10⁻²⁷ kg

speed of the alpha particle, c = 3 x 10⁸ m/s

The binding energy released is given by;

E_b = mc^2

where;

m is mass of the particle

c is speed of the particle

E = 6.64 x 10⁻²⁷ (3 x 10⁸)²

E = 1.992 X 10⁻¹⁸ J

Therefore, the binding energy released is 1.992 X 10⁻¹⁸ J

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3 years ago
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