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svetlana [45]
3 years ago
8

g a package of aluminum foil contains 50 ft2 of foil, which weighs approximately 8.0 oz. aluminum has a density of 2.70 g/cm3. w

hat is the approximate thickness of the foil in millimeters
Chemistry
1 answer:
VMariaS [17]3 years ago
8 0

Answer:

1.8×10^-2mm or 0.018mm

Explanation:

Density = mass/Volume

But volume= area×thickness

Area= 50ft2= 46451.52cm2

Mass=8oz= 226.7962g

Density= 2.70g/cm3

Thickness= mass/density ×area

= 226.7962/46451.52×2.70= 1.8×10-3cm= 1.8×10^-2mm

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If the moon resembled an asteroid, which theory would be most supported?
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What type of bonding is shown in the diagram
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Covalent Bond

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Which model can be used to trace genetic inheritance
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Convert 0.95 kilograms into centigrams. (1 g = 100 cg; 1 kg = 1000 g)
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95,000 centigrams

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6 0
3 years ago
Sodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride (CaCl2) is sometimes used for t
mihalych1998 [28]

Answer:

\Delta Tfp_{NaCl}= -14.0\°C\\\\\Delta Tfp_{CaCl_2}=-11.1\°C

Explanation:

Hello!

In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

\Delta Tfp= i*m*Kfp

Thus, we first need to compute the molality of each solute, as shown below:

m_{NaCl}=\frac{220.g/(58.44g/mol)}{1.00kg} =3.76m\\\\m_{CaCl_2}=\frac{220.g/(110.98g/mol)}{1.00kg} =1.98m

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

\Delta Tfp_{NaCl}= 2*3.76m*-1.86\°C/m=-14.0\°C\\\\\Delta Tfp_{CaCl_2}= 3*1.98m*-1.86\°C/m=-11.1\°C

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.

Best regards!

3 0
3 years ago
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