<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2
hope this helps</span>
The spacing between the fringes does not depend on the width of the slit.
The light intensity produced by the slits increases with increased width of the slit. The screen thus develops brighter fringes as the slit width increases.
On the screen, coloured fringes will be created if the white light replaces monochromatic light.
<h3>What is diffraction?</h3>
Diffraction is the breaking up of an electromagnetic wave as it passes a geometric structure (e.g. a slit), followed by reconstruction of the wave by interference. Diffraction occurs for all types of waves, including sound waves.
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Answer:
<em>It matters because crystalline and amorphous materials have different properties. The arrange affects the melting point (defined in crystals and a larger range in amorphous) and shape (geometrical in crystals, no geometrical in amorphous). </em>
Explanation:
The particles that compose a solid material are held in place by strong tractive forces between them when we analyze solids we consider the position of the atoms (molecules or ions) rather than their motion (which is important in liquids and gases). This positioning can be arranged in two general ways:
- Crystalline solids have internal structures that in turn lead to distinctive flat surfaces or face, these faces intersect at angles that are characteristic of the substance, crystals tend to have sharp, well defined and high melting points because of the same distance from the same number and type of neighbors. They generally have geometric shapes, some examples are diamonds, metals, salts.
- Amorphous solids produce irregular or curved surfaces when broken and they have poorly defined patterns when exposed to x rays because of their irregular array. In contrast with crystal solids, amorphous solids soften over a wide temperature range due to the different amounts of thermal energy needed to overcome different interactions. Some examples of these solids are gels, plastics, and some polymers.
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Answer:
Explanation:
B. Central Nervous System
The maximum height reached by the ball thrown by the boy is determined as 12.5 m.
<h3>
Angle of the projection</h3>
The angle of projection of the ball is calculated as follows;
R = u²sin2θ/g
- at maximum range, θ = 45 degrees
50 = u²/9.8
u² = 50 x 9.8
u² = 490
u = 22.14 m/s
<h3>Maximum height of the ball</h3>
H = u²sin²θ/2g
H = (22.14² x (sin45)²)/(2 x 9.8)
H = 12.5 m
Thus, the maximum height reached by the ball thrown by the boy is determined as 12.5 m.
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