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3 years ago

10

Signs that say "do not use near an open flame" refer to a(n) A) energy property. B) chemical property. C) physical property. D)

mechanical property.

1 answer:

sveta [45]3 years ago

8 0

Answer: B chemical

Explanation: it will make a chemical reaction

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Un ascensor sube con una velocidad constante de 2 m/s. Un niño que va en el ascensor lanza una piedra de 0.6 kg hacia arriba con

Natasha_Volkova [10]

Answer:

W = 7.5 J

Explanation:

W = KE

W = ½mv² = ½0.6(5²) = 7.5 J

Niño, piedra y ascensor están todos en el mismo marco de referencia inercial.

los 2 m / s no son importantes.

6 0

3 years ago

A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130

konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(c) W = 0J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

$W=Fd$ (1)

F: applied force = 130N

d: distance = 5.0m

$W=(130N)(5.0m)=650J$

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

$W_f=F_fd=\mu Mgd$ (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J$

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

$W = 0J$

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

$\Delta K=W_T$ (3)

You calculate the total work:

$W_T=Fd-F_fd=(F-F_f)d$ (4)

F: applied force = 130N

Ff: friction force

d: distance = 5.00m

The friction force is:

$F_f=(0.300)(36.0kg)(9.8m/s^2)=105.84N$

Next, you replace the values of all parameters in the equation (4):

$W_T=(130N-105.84N)(5.00m)=120.80J$

$\Delta K=120.80J$

The change in the kinetic energy of the box is 120.8J

(e) The final speed of the box is calculated by using the equation (3):

$W_T=\frac{1}{2}M(v_2^2-v_1^2)$ (5)

v2: final speed of the box

v1: initial speed of the box = 0 m/s

You solve the equation (5) for v2:

$v_2 = \sqrt{\frac{2W_T}{M}}=\sqrt{\frac{2(120.8J)}{36.0kg}}=2.58\frac{m}{s}$

The final speed of the box is 2.58m/s

5 0

3 years ago

quzilet The Magnet Recognition Program for health care organizations is based on fourteen forces of magnetism related to five ma

Lena [83]

Answer:

4. Personnel policies and programs

Explanation:

The Health care organizations that apply for Magnet status must demonstrate new ways of doing things and innovations in professional practice.

Personnel policies and programs is one of the forces of magnetism that impacts the structural empowerment of the organization.

The Personnel policies of an organization should provide an innovative environment in which the staff are developed and empowered. Empirical quality outcomes are reviewed by assessing the quality of care. New knowledge, innovations, and improvements are reviewed by assessing the quality improvement of the health care organization. Interdisciplinary relationships are assessed to review exemplary professional practice.

6 0

3 years ago

Quel est le gaz présent dans la couche d’ozone

stepan [7]

Answer:

L'ozone est produit à partir du dioxygène, composé de deux atomes d'oxygène(O2). Aux altitudes supérieures à 30 km, le rayonnement solaire possède encore une énergie suffisante pour casser une partie des molécules de dioxygène et libérer les atomes

3 0

3 years ago

fenix001 [56]

Answer:

D. The friction force increases by 9600 N.

Explanation:

Frictional force is directly proportional to kinetic coefient of friction.

6 0

4 years ago