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Cerrena [4.2K]
3 years ago
9

Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.

Physics
1 answer:
Step2247 [10]3 years ago
3 0
<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2 
hope this helps</span>
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b

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spectroscope or a spectrometer is an instrument which is used for separating the components of light, which have different wavel
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How fast would the International Space Station (ISS) have to travel to maintain a circular orbit a distance of 1400 km above the
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Answer:

The International Space Station move at 7.22 km/s.

Explanation:

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4 0
3 years ago
The magnetic field over a certain range is given by B~ = Bx ˆı + By ˆ, where Bx = 2 T and By = 4 T. An electron moves into the
krek1111 [17]

Answer:

Explanation:

The force exerted in a magnetic field is given as

F = q (v × B)

Where

F is the force entered

q is the charge

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Given that,

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v = 2•i + 6•j + 8•k. m/s

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Then note that,

V×B is the cross product of the speed and the magnetic field

Then,

F = q (V×B)

F = -1.602 × 10^-19( 2•i + 4•j +8•k × 2•i + 4•j)

Note

i×i=j×j×k×k=0

i×j=k. j×i=-k

j×k=i. k×j=-i

k×i=j. i×k=-j

F = -1.602 × 10^-19[(2•i + 4•j +8•k) × (2•i + 4•j)]

F = -1.602 × 10^-19 [2×2•(i×i) + 2×4•(i×j) + 4×2•(j×i) + 4×4•(j×j) + 8×2•(k×i) + 8×4•(k×j)]

F = -1.602 × 10^-19[4•0 + 8•k + 8•-k + 16•0 + 16•j + 32•-i]

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F = -1.602 × 10^-19(16•j - 32•i)

F = -1.602 × 10^-19 × ( -32•i + 16•j)

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Then, the x component of the force is

Fx = 5.126 × 10^-18 N

Also, the y component of the force is

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8 0
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Answer:
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7 0
3 years ago
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