two point charges of 3.4 μc and 6.6 μc are 0.20 m apart. what is the electrical potential energy of the system?
1 answer:
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Answer:
Final velocity is 181.61 m/s at angle 40.44° below horizontal.
Explanation:
Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s
Final horizontal velocity = 138.23 m/s
Considering vertical motion of projectile:
Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s
Acceleration, a = -9.81 m/s²
Displacement, s = -208 m
We have v² = u² + 2as
Substituting
v² = 98.96² + 2 x -9.81 x -208
v = 117.79 m/s
Final velocity,
Final velocity is 181.61 m/s at angle 40.44° below horizontal.