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Agata [3.3K]
3 years ago
15

. What number is half way between –9 and + 3. first one who gets this get brainliest

Mathematics
2 answers:
dusya [7]3 years ago
7 0
-6 that is the answer
strojnjashka [21]3 years ago
4 0
<span>We see the numbers on a number line

_____|___|___|___|___|___|___|___|___|___|___|___|___|____>
         -9   -8    -7    -6   -5    -4    -3    -2   -1     0    1      2    3
           <______________________________|_________>
                                         9                                       3
</span><span>You need to add both distances
</span><span>
|-9| + 3 = 9 + 3 = 12  

</span><span>half
</span><span>12 : 2 = 6


</span><span>Now , we measure the distance towards the center section
</span><span>1 way
-9 + 6 = -3
2 way
3 - 6 = -3

Answere : -3

</span>_____|___|___|___|___|___|___|___|___|___|___|___|___|____>
         -9   -8    -7    -6   -5    -4    -3    -2   -1     0    1      2    3
           <___________________|____________________>
                              <span>   6                                     6
</span><span>we used the average math
</span>| - 9 |  <span>means that the assumed value of -9 9 (positive )</span>
<span>


</span>
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Answer:

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Step-by-step explanation:

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4 0
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Multiply y^2-16/2y . 5y/y-4
alisha [4.7K]
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2



5 0
3 years ago
Solve this equation 53y - 55 = 42y
stiv31 [10]
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6 0
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The graph of is shown below. What is the value of y when x = 0?
jarptica [38.1K]

\huge\text{Hey there!}


\huge\textsf{This equation/question should be easy to}\\\\\huge\textsf{to solve for because, we have everything you}\\\\\huge\textsf{you will need on your graph and somewhat in}\\\\\huge\textsf{the question because it already gave you the}\\\\\huge\boxed{\mathsf{x-intercept}}\huge\textsf{.}
\mathsf{y = |x| - 2}

\mathsf{y = |0| - 2}

\mathsf{y = 0 - 2}

\mathsf{y = -2}
\huge\textsf{Therefore, your answer should be: }

\huge\boxed{\mathsf{y= }\frak{\ -2} \ \rm{(Option\ D.)}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>
~\frak{Amphitrite1040:)}</h3>
6 0
2 years ago
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