Answer:
a) 2L + 2W = 42
b) L = 2W + 3
c) The system is :
2L + 2W = 42
L - 2W = 3
( add the two equations )
3L + (2w - 2w) = 45
3L = 45
L = 45/3
L = 15 ( Length )
L - 2W = 3
15 - 2W = 3
2W = 15 - 3
W = 12/2
W = 6
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:
A. similar - AA
there's two corresponding angle that are equal!
Larry is a smart man, and he’s correct. (x+3)(4x-5)