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ElenaW [278]
3 years ago
7

There are ten members of the debate team: Ann, Bill, Carla, Don, Ed, Frank, Gretchen, Harry, Isabel, and Jen. If they randomly c

hoose three co-leaders of the group, what is the probability that Gretchen, Don, and Carla are chosen as the co-leaders?
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

1/120

Step-by-step explanation:

There are 10 members, and three are chose as co-leaders.  The number of possible combinations is:

₁₀C₃ = 120

One of those 120 combinations is Gretchen, Don, and Carla.  So the probability is 1/120, or approximately 0.83%.

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363 rounded to the nearest ten would be 360
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The correct answers are:

1. 35

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3. -88/3 or as a decimal, 29.3 repeating

4. 226.981

5. -6

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The probability that a household owns a pet is 0. 55. Suppose there are 5 houses on a block. Assuming each household is independ
Alexandra [31]

If the probability that a household owns a pet is 0.55 then the probability that all households will have pets is equal to 0.0503.

Given that the probability that a household owns a pet is 0.55 and there are 5 houses on a block.

We are required to calculate the probability that all the five households will have pets.

Probability is basicallly the chance of happening an event among all the events possible. It cannot be negative.

Binomial probability distribution is basically the probability calculations but in different combinations.

In this we have to calculate the probability that all the houses will have the pets then the probability that all five households will have pets is equal to 5C_{5}(0.55)^{5} (1-0.55)^{0}

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Hence the probability that all the five households will have pets is equal to 0.0503.

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6 0
1 year ago
9(2w−y)=21w−9y Solve for y
valentinak56 [21]

9(2w−y)=21w−9y

First you multiply the numbers in the parenthesis by 9

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subtract. 21w-18w=3w

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add. -9y+9y=0

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divide.

0=w

Final answer is 0.

5 0
3 years ago
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