De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
Answer:
Step-by-step explanation:
This was answered in question #24217201. It's the exact same question, but you forgot to put what parts A and B are. The answers and the work are there.
Answer:
C) At most one sample is mutated
Step-by-step explanation:
If there are 15 samples, it means that 15 is the total (100%) of samples. Then, if we know that there is a chance that 3% are mutated, then we calculate the 3% of 15:
This means that at most one sample is mutated, as this result is not zero (we discard answer A), and 0.45 is not more than half of the samples.
Answer:
BC = 10
Step-by-step explanation:
Since this is an isosceles triangle
AC = BC
3x-5 = 2x
Subtract 3x from each side
3x-5-3x = 2x-3x
-5 = -x
Multiply each side by -1
5 =x
BC = 2x
=2 *5
BC =10
