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kondaur [170]
3 years ago
7

WILL MARK BRAINIEST: Find the equation in slope intercept form for each line described. a line that passes through the point (8

4) and is parallel to the line 3x-4y=20.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
5 0

y=mx+b

y=24x-5

Please mark brainliest.

I have also used an online algebra calculator to check my answer so this is correct.

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MATH WORD PROBLEM
Sloan [31]

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

<h3><u>Solution:</u></h3>

Let "r" be the cost of one regular admission ticket

Let "s" be the cost of one senior citizen ticket

Given that,

<em><u>On day 1 you sold 30 Regular Admission tickets and  20 Senior Citizen tickets for a total of $400</u></em>

So we can frame a equation as:

30 Regular Admission tickets x cost of one regular admission ticket + 20 Senior Citizen tickets x cost of one senior citizen ticket = $ 400

30 \times r + 20 \times s = 400

30r + 20s = 400 ----- eqn 1

<em><u>Day two you sell 40 Regular Admission tickets and only 10 Senior  Citizen tickets for a total of $450</u></em>

So we can frame a equation as:

40 Regular Admission tickets x cost of one regular admission ticket + 10 Senior Citizen tickets x cost of one senior citizen ticket = $ 450

40 \times r + 10 \times s = 450

40r + 10s = 450 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "r" and "s"</u></em>

Multiply eqn 2 by 2

80r + 20s = 900 --- eqn 3

Subtract eqn 1 from eqn 3

80r + 20s = 900

30r + 20s = 400

(-) ---------------------

50r = 500

<h3>r = 10</h3>

Substitute r = 10 in eqn 1

30r + 20s = 400

30(10) + 20s = 400

300 + 20s = 400

20s = 100

<h3>s = 5</h3>

<em><u>Thus we have:</u></em>

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

4 0
4 years ago
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