Step-by-step explanation:
start from f(g(x))
f(g(x))= 3(g(x)) -2
f(g(x))= 6x -2
h(f(g(x)))=(f(g(x)))² -5(f(g(x)))
h(f(g(x)))=(6x-2)² -5(6x-2)
h(f(g(x)))=36x²-24x+4-(30x-10)
h(f(g(x)))=36x²-24x+4-30x+10
h(f(g(x)))=36x²-54x+14
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Voy a decir que son 5 litros
Answer: See explanation
Step-by-step explanation:
a. The deposit
= 15% × $2975
= 15/100 × $2975
= 0.15 × $2975
= $446.25
b. The hire purchase price
Outstanding balance = $2975 - $446.25 = $2528.75
20% of outstanding balance
= 20% × $2528.75
= 0.2 × $2528.75
= $505.75
Hire purchase price
= $2975 + $505.75
= $3480.75
c. The difference the hire purchase price and cash price
= $3480.75 - $2975
= $505.75
d. The difference as a percentage of the cash price.
= ($505.75 / $2975) × 100
= 0.17 × 100
= 17%
Answer:
Only line A is a well-placed line of best fit.
Step-by-step explanation:
I did this on Plato and got it correct.
