For this case we have that given two functions, 
and 
, then
is given by:
So:
We have to:
Answer:
Option C
Answer:
The solution set is {-8, 5}.
Step-by-step explanation:
a^2 + 3a – 40 = 0 .
We need 2 numbers whose product is -40 and whose sum is +3.
They would be + 8 and - 5, so we have the factors:
(a + 8)(a - 5) = 0
Now either a + 8 = 0 or a - 5 = 0, so:
a = -8 or 5.
Answer:
One
Step-by-step explanation:
(x + 12) = 4x - 1
x + 12 = 4x - 1
12 = 3x - 1
13 = 3x
x = 13/3 = 4.3333333...
Since x only has one value, only one solution exists for the equation.
6 = 5r - 14
6 + 14 = 5r
20 = 5r
r = 4
Answer:
76
Step-by-step explanation:
I made a chart to simplify it
1 | -8
2| -2
3| 4
4| 10
5| 16
6| 22
7| 28
8| 34
9| 40
10| 46
11| 52
12| 58
13| 64
14| 70
15| 76
