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loris [4]
3 years ago
15

What is the meaning of pseudopod? A. true foot B. true hand C. false foot D. false hand

Chemistry
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

C. False foot

Explanation:

tankabanditka [31]3 years ago
6 0

Answer: Pseudopodia are temporary and cytoplasm-filled parts of the cell membrane that are able to change their form in order to move. They are used in some eukaryotic cells to move around or to eat. Most cells that do this are called amoeboids.

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What is the pH of a 1.7 × 10⁻⁴ M HClO₄ solution?
Mamont248 [21]
Ph= -log[h30]

Ph= -log[1.7x10^-4]

pH= 3.77

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3 0
3 years ago
Energy is transferred
Andrei [34K]
True is the right oneee
6 0
3 years ago
A gas occupies 1.00 L at standard temperature. What is the volume at 333.0°C?
AURORKA [14]
We use Charles's Law: V1/T1=V2/T2

Standard Temperature: 0 degree Celsius= 273K
333.0 degrees Celsius= 606K

Set up: (1.00L)/ (273K)= V2/ (606.0K)
⇒ V2= (1.00L)/ (273K)* (606.0K)= 2.22L

Hope this would help :))

7 0
3 years ago
Is a bimolecular reaction necessarily second-order? Is a second-order reaction necessarily bimolecular? Answer, with explanation
Kruka [31]
A bimolecular reaction is always a second-order reaction, but a second-order reaction is not always a bimolecular reaction.

The most important thing to take note of is that molecularity of a reaction is a concept applicable to only elementary reactions, meaning non-complex. In a way, elementary reactions are basic and achieved in one step. Complex reactions involve intermediate steps before achieving the desired reaction.

Molecularity is equal to the sum of the coefficients of the reactants, so two reactants give a second-order bimolecular reaction. However, second-order reactions can involve more than two reactants especially in complex reactions.
3 0
3 years ago
PLEASE HELP!! A gas has a volume of 7.9 L at a temperature of 222. K and pressure of 877 mmHg. What is the new temperature (in C
Natali5045456 [20]

Answer:

82.97 K

Explanation:

Applying,

PV/T = P'V'/T'................ Equation 1

Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

Make T' the subject of formula in equation 1

T' = P'V'T/PV................ Equation 2

From the question,

Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L

Substitute these values into equation 2

T' = (0.327×10.41×222.2)/(1.154×7.9)

T' = 82.97 K

Hence the new temperature is 82.97 K

7 0
3 years ago
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