Question

How many moles of oxygen gas can 0.882 mol of hydrogen peroxide produce if decomposition is complete? 2H2O2 (l) → 2H2O(l) + O2(g)

Answer 1

We are given the chemical reaction and the amount of reactant used for the process. We use these data together to obtain what is asked. We do as as follows:

0.882 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 0.441 mol O2 produced

Hope this answers the question.

Answer 2

Answer : The moles of oxygen gas will be, 0.441 mole

Explanation : Given,

Moles of $H_2O_2$ = 0.882 mole

The given balanced chemical reaction is,

$2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g)$

From the balanced reaction we conclude that

As, 2 moles of $H_2O_2$ react to give 1 mole of $O_2$

So, 0.882 moles of $H_2O_2$ react to give $\frac{0.882}{2}=0.441$ moles of $O_2$

Therefore, the moles of oxygen gas will be, 0.441 mole