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Ugo [173]
3 years ago
10

1/ Which graph illustrates constant speed and velocity

Chemistry
1 answer:
Maksim231197 [3]3 years ago
4 0
Velocity is said to be constant if its magnitude as well direction at any instant is remains the same. In D, if you draw a line parallel to y-axis at any time t, you can see that velocity is same. Hence, D is the correct graph.

The kinetic energy of gaseous molecules is greater than that of liquid molecules. Therefore, in gas, kinetic energy overcomes the force of attraction between molecules. In short, in gas phase, particles move at high speed and hence they have less force of attraction. In case of liquid phase, particles are close enough as a result there is much more force of attraction compared to gaseous molecules. In liquid state, kinetic energy cannot overcome force of attraction therefore, liquid molecules slow down.

Therefore, B is the correct answer.
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A mineral forms from water at the edge of a lake.
irga5000 [103]

Answer:C

Explanation:The mineral is only formed when hot water cooler

8 0
3 years ago
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How can toxicant absorption be reduced after exposure to the skin? How can absorption be reduced for orally consumed chemicals?
zmey [24]

Answer:

The toxicant absorbtion can be reduced after exposure to the skin the surrounding clothing shoes or gloves should be removed or torn off than the part of the body which was exposured to the toxicant should be immediatly washed using clean running water for a while, with cold shower being the most recommended splashing method. In case of absorption for orally consumed chemicals should check on any remaining toxicant residue and be removed from the mouth. Vomiting should be induced to patients that are still conscious by providing them with liquids that can provoke vomiting. This will help in removing the toxicant in the intestinal and reduce their effect. Gastric lavage should then be done to induce diarrhea.  

Explanation:

4 0
3 years ago
I WILL GIVE BRAINLIEST!!!!!
Alexxx [7]
                                    HNO₃ + H₂S → S + NO + H₂<span>O

Assign Oxidation Number:

                                L.H.S                               R.H.S
           N in HNO</span>₃  =  +5                                     +2  =  N in NO
               S in H₂S  =  -2                                       0  =  S in S

Write Half cell Reactions:
Reduction Reaction:
                                 
3e⁻  +   HNO₃   →   NO      -------(1)
Oxidation Reaction:
                                  H₂S   →   S  +  2e⁻             -------(2)

Multiply eq. 1 with 2 and eq. 2 with 3 to balance electrons. 

                                          6e⁻  +   2 HNO₃   →   2 NO
                                    
                                             3 H₂S   →   3 S  +  6e⁻
                                                                                  Cancel e⁻s,
                                 ______________________________
                               
                             2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  H₂O

Balance Oxygen Atoms by multiplying H₂O with 4, Hydrogen atoms will automatically get balance.

                            2 HNO₃  +  3 H₂S   →   2 NO  +  3 S  +  4H₂O


                                
4 0
3 years ago
Density (D) is defined as the ratio of mass (m) to volume (V) and can be determined from the expression D = . Find the density o
olchik [2.2K]

Explanation:

87.329 g/32.32 cm³ = 2. 70 g/cm³

4 0
2 years ago
While exploring a coal mine, scientists found plant fossils in the ceiling of the mine which had been preserved by an earthquake
ale4655 [162]

Answer:

11552.45 years

Explanation:

Given that:

Half life = 5730 years

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{5730}\ years^{-1}

The rate constant, k = 0.00012 years⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 0.00012 years⁻¹

Initial concentration [A_0] = 160.0 counts/min

Final concentration [A_t] = 40.0 counts/min

Time = ?

Applying in the above equation, we get that:-

40.0=160.0e^{-0.00012\times t}

e^{-0.00012t}=\frac{1}{4}

-0.00012t=\ln \left(\frac{1}{4}\right)

t=11552.45\ years

7 0
3 years ago
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