Answer:
Optimum pH= 6
Optimum pH for the given enzyme would be the average of pKa values of two amino acids (2.9 + 9.1 /2= 6)
Explanation:
The pKa represents the association constant of amino acids. It is calculated by taking the negative log value of the ratio of a dissociated acid and the conjugated base which in turn regulates the isoelectric point (pI) of the protein.
The amino acids present in the active site of the enzyme regulate the interaction of enzyme and substrate. The given enzyme contains two ionizable amino acids with pKa values of 2.9 and 9.1 respectively. Therefore, the optimum pH of the given enzyme would be 2.9 + 9.1 / 2 = 12/2 = 6.
At pH 6, both the ionizable amino acids would serve as a good buffer with their active proton donor and proton acceptor species.
Producers:
One example of producers found in food chains include plants. They use photosynthesis to make their own food. Examples of plants include trees, grass, moss, flowers, and weeds, to name a few.
Primary consumers are herbivores, feeding on plants. Caterpillars, insects, grasshoppers, termites and hummingbirds are all examples of primary consumers because they only eat autotrophs (plants).
Types of Secondary Consumers
Spiders, snakes, and seals are all examples of carnivorous secondary consumers. Omnivores are the other type of secondary consumer. They eat both plant and animal materials for energy. Bears and skunks are examples of omnivorous secondary consumers that both hunt prey and eat plants.
In the real world, a tertiary consumer can eat many different animals and even plants sometimes. This means that they can actually be carnivorous or omnivorous. Some examples of tertiary consumers include, birds of prey, big cats, and foxes.
Answer: <em>The total amount of energy in an ecosystem remains the same</em>
Hope this helped !
Explanation:
