<h3>The expression for the length of fabric used for each doll is
</h3>
<em><u>Solution:</u></em>
Given that,
Margaret has 16 yards of fabric
she is making dresses for z doll
Therefore,
Total length of fabric = 16 yards
Number of dresses = z dolls
Therefore,
Thus, the expression for the length of fabric used for each doll is
He used 53 pounds. I got this by using two equations.
a+b=117
and
5.8a+4.1b= 569.8
I took the first equation and subtracted 'b' so the equation looked like a=117-b.
I then plugged in 117-b into the second equation, so it ended up looking like this:
5.8 (117-b)=569.8
5.8 times 117 is 678.6. And 5.8 times negative b is negative 5.8b.
The equation now looks like this:
678.6-5.8b+4.1b=569.8
Add like terms
678.6-1.7b=569.8
Then subtract 678.6 from both sides
-1.7b= -108.8
divide each side by -1.7
you get b= 64.
But because you are looking for how many pounds for a, subtract 64 from 117. You get 53. 53 is the answer.
Luke's original decimal is 0.20 and Bekka's is 0.30 so 0.40 and 0.50 would be greater than Luke's original and 0.20 and 0.10 are lesser than Bekka's original decimal
Answer:
Step-by-step explanation:
let 
denote grams of 
formed in 
mins.
For 
of we have:
of A and 
of B
Amounts of A,B remaining at any given time is expressed as:
of A and 
of B
Rate at which C is formed satisfies:
Apply the initial condition,
,to the expression above
Now at 
:
Substitute in X(t) to get
