A and 0 both equals 45 degrees
Answer:
=0.1587 or 15.87%
So option A is correct answer so 15.87% of the invoices were paid within 15 days of receipt.
Step-by-step explanation:
In order to find the percent of the invoices paid within 5 days of receipt we have to find the value of Z first.

where:
X is the random varable which in our case is 15 days
u is the mean or average value which is 20 days
S is the standard deviation which is 5 days

Z=-1.0
We have to find Probability at Z less than -1
P(Z<-1.0) which can be written as:
=1-P(Z>1.0)
From Cumulative distribution table:
=1-(0.3413+0.5)
=0.1587 or 15.87%
So option A is correct answer so 15.87% of the invoices were paid within 15 days of receipt.
Answer:
The entry has an area of __44___ square feet
The total area of the tree house is __345__ square feet
Step-by-step explanation:
Let's first calculate the area of the trapezoid entrance:
The area of a trapezoid is given by:
A =((b1 + b2) * h) / 2
Where b1 and b2 are the bases or parallel sides. So, we have:
A = ((6 + 16) * 4) / 2 = (22 * 4) / 2 = 44 sq ft
Now, let's look at the other areas... which are all rectangles, so easy to calculate (b * h).
Playroom: 16 x 14 = 224 sq ft
Side Deck: 3 x 14 = 42 sq ft
Back Porch: 6 x6 = 35 sq ft
So, in the total area of the tree house is:
TA = 44 + 224 + 42 + 35 = 345 sq ft
Answer:
backflip cartwheel
Step-by-step explanation:
Answer:
a. 0.0000
b. 0.9949
c. 0.0212
d. 1.0000
Step-by-step explanation:
a. This is a binomial probability distribution problem of the form:

#Given n=15, p=0.56, the probability of none will order a non-alcoholic drink:


Hence, the probability that none will order a non-alcoholic drink is 0.0000
b. The probability that at least 4 will order a non-alcoholic drink is:

Hence, the probability of at least 4 non-alcoholic orders is 0.9949
c. The Probability that fewer than 5 orders will be made is calculated as:

Hence, the probability of less than 5 orders is 0.0212
d. The probability of all orders being non-alcoholic is equivalent to 1 minus no order being non-alcoholic.
-From a above, the probability of zero non-alcoholic order is , P(X=0)=0000045
-Therefore:


Hence, the probability that all orders are non-alcoholic 1.0000