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scoray [572]
4 years ago
12

a number n is 25% of some number a and 35% of a number b. is a > b,a<, or is it impossible to determine the relationship

Mathematics
1 answer:
Anit [1.1K]4 years ago
6 0
Answer:   "It is IMPOSSIBLE to determine the relationship."
_________________________________________________________
 Because number "a" could be "30" ; and number "b" could be: "6 trillion"; for example.  Or, number "a" could be "6 trillion" and  number "b" could be "30".

OR;  "a" could equal "b" ; for example.
_________________________________________________________
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That depends on the total distance of the race, which you
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5 0
3 years ago
Your Turn: Using the figure, a
yawa3891 [41]
The first thing you should see in this case is that the triangles are proportional.
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 Step 2:
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4 0
3 years ago
Solve for x 4/x + 4/x^2-9= 3/x-3
Goshia [24]

\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}\qquad\text{subtract}\ \dfrac{4}{x^2-9}\ \text{from both sides}\\\\\dfrac{4}{x}=\dfrac{3}{x-3}-\dfrac{4}{x^2-9}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{4}{x}=\dfrac{3}{x-3}-\dfrac{4}{x^2-3^2}\\\\\dfrac{4}{x}=\dfrac{3}{x-3}-\dfrac{4}{(x-3)(x+3)}\\\\\dfrac{4}{x}=\dfrac{3(x+3)}{(x-3)(x+3)}-\dfrac{4}{(x-3)(x+3)}\qquad\text{use distributive property}\\\\\dfrac{4}{x}=\dfrac{3x+9-4}{(x-3)(x+3)}\\\\\dfrac{4}{x}=\dfrac{3x+5}{x^2-9}\qquad\text{cross multiply}

4(x^2-9)=x(3x+5)\qquad\text{use distributive property}\\\\4x^2-36=3x^2+5x\qquad\text{subtract}\ 3x^2\ \text{and}\ 5x\ \text{from both sides}\\\\x^2-5x-36=0\\\\x^2-9x+4x-36=0\\\\x(x-9)+4(x-9)=0\\\\(x-9)(x+4)=0\iff x-9=0\ \vee\ x+4=0\\\\\boxed{x=9\ \vee\ x=-4}

8 0
4 years ago
I need help with this please​
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Answer:

C

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3 0
4 years ago
Write these expressions as an equation
Novay_Z [31]

Answer:

Let the number be x

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8 0
4 years ago
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