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Wewaii [24]
3 years ago
10

A builder is buying property where she can build new houses. The line plot shows the sizes of the lots for each house. What is t

he average size of the lots?

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

Step-by-step explanation:

Oh yes daddy harder

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If a₁ = 4 and an = 5an-1 then find the value of a5.
igor_vitrenko [27]

The value of a_{5} is 2500, when a_{1}=4 and 5a_{n-1}.

Given that, a_{1}=4 and 5a_{n-1}.

We need to find the value of a_{5}.

<h3>What is an arithmetic sequence?</h3>

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of a_{5} :

a_{2} =5a_{2-1}=5a_{1}=5 \times4=20

a_{3} =5a_{3-1}=5a_{2}=5 \times20=100

a_{4} =5a_{4-1}=5a_{3}=5 \times100=500

a_{5} =5a_{5-1}=5a_{4}=5 \times500=2500

Therefore, the value of a_{5} is 2500.

To learn more about arithmetic sequence visit:

brainly.com/question/15412619.

#SPJ1

5 0
2 years ago
Solve for q.<br> mn + q = p<br><br> q = p - mn<br> q = p (mn )<br> q = p + mn
cupoosta [38]
It would be your first answer because since the MN is a positive you have to subtract it to move it to P and you solved for Q
6 0
3 years ago
The independent-samples t testResearch Scenario: A forensic psychologist has developed a new program that teaches empathy and po
8_murik_8 [283]

Answer:

Step-by-step explanation:

Hello!

The researcher developed a treatment to teach social skills to youth offenders. To test if the treatment is effective in increasing empathy compared to the standard treatment she randomly selected a group of 9 offenders and applied the new treatment and to another group of 9 randomly selected youth offenders, she applied the standard treatment. (Note: the data corresponds to two samples of 9 units each, so I've used those sizes to conduct the test)

At the end of the treatment, she administers BES to measure their empathy levels. Her claim is that the offenders that received the new treatment will have higher BES scores than those who received the standard treatment.

1) Using the records obtained for both groups, she  intends to conduct an independent t-test to analyze her claim.

X₁: BES results of a youth offender treated with the new treatment.

X₂: BES results of a youth offender treated with the standard treatment.

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

α:0.05

test statistic

t_{H_0}= -0.32

p-value: 0.7517

The p-value is greater than the significance level so the decision is to not reject the null hypothesis. This means that at a 5% significance level you can conclude that there is no difference between the mean BES scores of the youth offenders treated with the new treatment and the mean BES score of  the youth offenders treated with the standard treatment. The new treatment doesn't increase the levels of social empathy of the youth offenders.

I hope this helps

(Box plot in attachment)

7 0
4 years ago
Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. a
liberstina [14]
First plane: 496x
<span>Second plane:  558( x - 1/2) </span>

<span>Equation: 496x = 558( x - 1/2) </span>

<span>Solving  x = 9/2 ,  or  x = 4.5 hours.

Hope this helps.</span>
7 0
3 years ago
Help Me Please~
Mkey [24]

Answer:

45^0.999

Step-by-step explanation:

The bases are equal so we wont divide them, we shall only divide the exponents.

<em>2799/2800=0.999</em>

<em>hope it helps</em>

3 0
3 years ago
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