Volume of cylinder is 402.1238....=402.12ft
Volume of rectangle is 1344ft
Add both together= 1746.12ft

Surface area of rectangle:
Length=14ft
width= 8ft
height =12ft

14x12=168x2=336
8x12=96x2=192
14x8=112x2=224
336+192+224=752

Surface Area of cylinder:

Radius= 4ft
height=8ft
2π r h+2π r^2
2π4(12)+2<span>π4^2
2</span>π48+2<span>π16
301.59+100.53=402.42ft

Add both surface area together=1154.12ft</span>

5 0

3 years ago

Help please I’ll mark brainliest!!!! Which of the following graphs is a function of x?

Scrat [10]

I think it’s either D or A,
So sorry if I’m wrong

7 0

3 years ago

Given frequent itemset l and subset s of l, prove that the confidence of the rule "s’ => (l - s’)" cannot be more than the co

aniked [119]

Answer:

the answer is I

Step-by-step explanation:

4 0

4 years ago

Suppose you flip a fair coin N times. Let random variable h be the number of heads that occur. Use the normal approximation to e

Mariana [72]

Answer:

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

Step-by-step explanation:

Since the coin is fair, then the probability that a filp is heads is 1/2. Given N tries, the amount of heads can be approximated with a Normal distribution with mean μ = N *1/2 = N/2 and standard deviation σ = √(N*1/2 * 1/2) = √N/ 2

The density function of that random variable is given by de following formula

$f_X(k) = \frac{1}{\sqrt{2\pi} * \sigma} e^{\frac{-(k-\mu)^2}{2\sigma^2} } = \frac{2}{\sqrt{2\pi N}} e^{\frac{-2(k-N/2)^2}{N} }$

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

4 0

3 years ago