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3 years ago

12

Match the term to the correct definition

1 answer:

bearhunter [10]3 years ago

4 0

Mechanical Waves are waves which propagate through a material medium (solid, liquid, or gas) at a wave speed which depends on the elastic and inertial properties of that medium. There are two basic types of wave motion for mechanical waves: longitudinal waves and transverse waves. The animations below demonstrate both types of wave and illustrate the difference between the motion of the wave and the motion of the particles in the medium through which the wave is travelling.

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37 Questions - All Questions Are Required

ANTONII [103]

Acceleration = vf-vi /t
10-22/3=2.6m/s^2

5 0

3 years ago

Read 2 more answers

An astronomer at the equator measures the Doppler shift of sunlight at sunset. From this, she calculates that Earth's tangential

Ksivusya [100]

Answer : Radius of Earth is 6,340 Km.

Explanation

It is given that,

Tangential velocity of Earth at the equator, v = 465 m/s

Centripetal acceleration at the equation is, $a_c=3.41\times 10^{-2}\ m/s^2$

We know that the relation between centripetal acceleration and tangential velocity is :

$a_c=\dfrac{v^2}{r}$ ..........(1)

Where,

v is tangential velocity

r is the radius

Putting all values in equation (1)

$3.41\times 10^{-2}\ m/s^2=\dfrac{(465 m/s)^2}{r}$

$r=6340909\ m$

or

$r=6,340\ Km$

The Earth's radius is 6,340 Km. Hence, this is the required solution.

7 0

4 years ago

What are the highlands of the moon called?<br> A) Maria<br> B) Terrae<br> C)Regolith<br> D)Crater

marissa [1.9K]

Answer:

C)Regolith

PLEASE GIVE BRAINLIEST

8 0

3 years ago

Read 2 more answers

Phoebe removes frozen vegetables from the freezer to make herself a stir fry she’s in a bit of a hurry so she immersed the plast

mr_godi [17]

Thermal conduction! :)

5 0

3 years ago

Read 2 more answers

A bowling ball is far from uniform. Lightweight bowling balls are made of a relatively low-density core surrounded by a thin she

Leni [432]

Answer:

Part a)

$I = 17.4 \times 10^{-3} kg m^2$

Part b)

$I = 14.9 \times 10^{-3} kg m^2$

Explanation:

Part a)

Moment of inertia of the core of the ball

$I_1 = \frac{2}{5}m_1r_1^2$

$I_1 = \frac{2}{5}(1.6)((\frac{0.196}{2})^2)$

$I_1 = 6.14 \times 10^{-3} kg m^2$

now the moment of inertia for thin shell

$I_2 = \frac{2}{3} m_2r_2^2$

$I_2 = \frac{2}{3}(1.6)((\frac{0.206}{2})^2)$

$I_2 = 11.3 \times 10^{-3} kg m^2$

now total inertia of the ball is given as

$I = I_1 + I_2$

$I = 17.4 \times 10^{-3} kg m^2$

Part b)

Moment of inertia of uniform ball of mass 3.2 kg

$I = \frac{2}{5} mr^2$

$I = \frac{2}{5}(3.2)((\frac{0.216}{2})^2)$

$I = 14.9 \times 10^{-3} kg m^2$

4 0

4 years ago