THere is a standard relationship that gives this result where the capacity of the capacitor is used:

.
We know though that Q/c=V and thus we can use the relationship:
E=Q*V/2 where we have just substituted in. If we also take into account that Q=VC, we can also get that E=V^2*C/2.
We are given the charge and the potential, so the best expression to use is the middle one.
Substituting, we get that E=1/2*8*10^(-10)*20=8*10^(-9).
The answer is B
Solution :
The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :
F = ma
F = qvB and 
Substituting these values in the second law of Newton,

Now solving for B, we get:


= 0.261 T
The field strength can be obtained by using the technology of today.
Answer:
Speed of water at the top of fall = 5.40 m/s
Explanation:
We have equation of motion

Here final velocity, v = 26 m/s
a = acceleration due to gravity

displacement, s = 33 m
Substituting

Speed of water at the top of fall = 5.40 m/s
suitcase can be pushed to a distance of 0.35 m
Explanation:
Work done= Ff d
w= 670 J
Ff= force of friction
d= distance
force of friction is given by Ff=μ mg
μ= coefficient of friction=2.76
m=mass=71.5 kg
so Ff= (2.76) (71.5) (9.8)
Ff=1934 N
so W= Ff d
670= 1934 d
d=0.35 m