
★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

★ The speed of the hound and the hare

★ The speed of the hound and the hare = 25:18

As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.
So firstly let us assume a metres as the distance covered by the hare in one leap.
Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.
But 3 leaps of the hound are equal to 5 leaps of the hare.
Henceforth, (5/3)a meters is the distance that is covered by the hound.
Now according to the question,
Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)
Now the distance travelled by the hound in it's 5 leaps..!
Now the distance travelled by the hare in it's 6 leaps..!
Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!
You are looking at yourself in a plane mirror, a distance of 3 meters from the mirror. your brain interprets what you are seeing in the mirror as being a person standing 6 meters from you.
<h3>Calculation</h3>
The plane mirror shows an exact replica of the real world. that means the distance of you from the mirror is the same distance as your reflection form the mirror at the opposite side of the mirror.
Thus, distance of image from the plane mirror is same as the distance of object (person) from the plane mirror but the image is formed behind the mirror.
Thereby we have v=u=3 m
Thus, distance between image and the person
is d = v + u = 3 + 3 = 6 m
Thus, the person is 6 meters away from the image.
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I have the answer for A. Since there is blockage in the ear canal, some sound waves may not be able to get through or travel as quickly so you would have trouble hearing
A force is the push or pull acting on an object as a result of its interaction with another object. Here the net force acting on the box is 297 N
From the question
Given that,
Mass of the box ,m = 102 kg
Acceleration of the box ,a = 2.5 m/s²
Frictional force acting between the box and the floor ,<em>f =</em> 42 N
Here we have to find the net force acting on the body, F = ?
By Newton's second law of motion,
∑F = ma,
where, F is the net force
m is the mass of the body
a is the acceleration of the moving body
If the body is considered moving in the x-direction then,
F-<em>f = ma</em>
<em>F - 42 = 102 x 2.5</em>
<em> = 255</em>
<em>F = 255 + 42 = 297 N </em>
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Here in this case since there is no torque about the hinge axis for the system of bullet and block then we can say that angular momentum of this system will remain conserved


here we will have
L = 0.250 m
v = 385 m/s
m = 1.90 gram
now moment of inertia of the plate will be



now from above equation

